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juin [17]
4 years ago
15

The start-up cost to join eTunes music is $7.95 plus $0.95 per song downloaded. If Will spent $26, write and solve a linear equa

tion to find how many songs he downloaded .
Mathematics
1 answer:
Oksanka [162]4 years ago
6 0
Y = 0.95x + 7.95
26 = 0.95x + 7.95
Solve for x
26-7.95 =0.95x
18.05/0.95 = x
X = 19 songs
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Varun’s neighborhood is having a Halloween party. His family donated 9 bags of candy with 115 pieces in every bag. Christy’s fam
valina [46]

Answer :

Step-by-step explanation:

His family donated 9 bags of candy with 115 pieces in every bag.

Christy’s family donated 25 bags of candy with 40 pieces of candy in every bag.

Christy ate 10 pieces of candy and Varun ate 15 pieces of candy.

How many pieces of candy are left to give out?

Christy : 30

Varun :100

If there are 50 kids in the neighborhood, how many pieces will each child receive?

130 divided by 50 =2.6

but that wont be right so 2 pieces per child

6 0
3 years ago
Read 2 more answers
A farmer builds a fence to enclose a rectangular pasture. He uses 160 feet of fence. Find the total
givi [52]
Since the problem said he uses 160 feet of fence, you know that is the perimeter
P = 2l + 2w
You know that one of the dimensions is 50, so you can plug that into the equation
160 = 2 x 50 + 2w
160 = 100 + 2w
2w = 60
w = 30
The area is equal to l x w 
50 x 30 = 1500 square feet
8 0
3 years ago
Find the common ratio of the geometric sequence. 9,-18, 36, -72
Agata [3.3K]

Answer:

according to me its just multiplying with the number ( -2)

like 9×(-2) = -18

36×(-2) = -72

5 0
2 years ago
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Use the given transformation to evaluate the integral. double integral 9xy dA R , where R is the region in the first quadrant bo
lianna [129]

It looks like the boundaries of R are the lines y=\dfrac23x and y=3x, as well as the hyperbolas xy=\frac23 and xy=3. Naturally, the domain of integration is the set

R = \left\{(x,y) ~:~ \dfrac{2x}3 \le y \le 3x \text{ and } \dfrac23 \le xy \le 3 \right\}

By substituting x=\frac uv and y=v, so xy=u, we have

\dfrac23 \le xy \le 3 \implies \dfrac23 \le u \le 3

and

\dfrac{2x}3 \le y \le 3x \implies \dfrac{2u}{3v} \le v \le \dfrac{3u}v \implies \dfrac{2u}3 \le v^2 \le 3u \implies \sqrt{\dfrac{2u}3} \le v \le \sqrt{3u}

so that

R = \left\{(u,v) ~:~ \dfrac23 \le u \le 3 \text{ and } \sqrt{\dfrac{2u}3 \le v \le \sqrt{3u}\right\}

Compute the Jacobian for this transformation and its determinant.

J = \begin{bmatrix}x_u & x_v \\ y_u & y_v\end{bmatrix} = \begin{bmatrix}\dfrac1v & -\dfrac u{v^2} \\\\ 0 & 1 \end{bmatrix} \implies \det(J) = \dfrac1v

Then the area element under this change of variables is

dA = dx\,dy = \dfrac{du\,dv}v

and the integral transforms to

\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \int_{\sqrt{2u/3}}^{\sqrt{3u}} \frac{dv\,du}v

Now compute it.

\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \ln|v|\bigg|_{v=\sqrt{2u/3}}^{v=\sqrt{3u}} \,du \\\\ ~~~~~~~~ = \int_{2/3}^3 \ln\left(\sqrt{3u}\right) - \ln\left(\sqrt{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln(3u) - \ln\left(\frac{2u}3\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln\left(\frac{3u}{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \int_{2/3}^3 du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \left(3-\frac23\right) = \boxed{\frac76 \ln\left(\frac92\right)}

7 0
2 years ago
Haley makes earrings and packages them into cube boxes that measure 1/6 foot wide. How many 1/6 foot cubic boxes can she fit int
alexandr402 [8]

Answer:  28 cube boxes.

Step-by-step explanation:

The volume of a cube can be found with this formula:

V_{(c)}=s^3

Where "s" is the lenght of any edge of the cube.

 You need to find the volume of a cube box:

V_1=s^3=(\frac{1}{6}ft)^3=\frac{1}{216}ft^3

To find the volume of the shipping box, first we must convert the mixed number to  an improper fraction. To do it, multiply the whole number part by the denominator of the fraction and add this product to the numerator.

The denominator does not change.

Then:

1\ \frac{1}{6}=\frac{(1*6)+1}{6}=\frac{7}{6}

Knowing the dimensions of the shipping box, you can calculate its volume by multiplying its dimensions. Then, this is:

V_2=(\frac{7}{6}\ ft)(\frac{1}{3}\ ft)(\frac{1}{3}\ ft)=\frac{7}{54}\ ft^3

Finally, in order to find the  number of cube boxes can Haley fits into a shipping box, you must divide the the volume of the shipping box by the volume of one cube:

\frac{\frac{7}{54}ft^3}{\frac{1}{216}ft^3}=28

5 0
3 years ago
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