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Travka [436]
3 years ago
14

Strontium-90 is a radioisotope that will decrease in mass by one-half every 29 years. How many years will it take for a 10.0-gra

m sample of strontium-90 to decay to 5.00 grams?
Chemistry
1 answer:
Lelechka [254]3 years ago
7 0

Answer: It will take 29 years for a 10.0-gram sample of strontium-90 to decay to 5.00 grams

Explanation:

Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations. The radioactive decay follows first order kinetics.

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

Half life is represented by t_{\frac{1}{2}

t_{\frac{1}{2}=\frac{0.693}{\lambda}

\lambda = rate constant

Given : Strontium-90 decreases in mass  by one-half every 29 years , that is half life of Strontium-90  is 29 years.

As half life is independent of initial concentration, it will take 29 years for a 10.0-gram sample of strontium-90 to decay to 5.00 grams as the amount gets half.

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Answer:

d. the conjugate base of the weak acid

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How many grams of CO2 are in 10 mol of the compound?
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olchik [2.2K]

_____________________________________________

<h2 /><h2 /><h2><u>Solution </u><u>3</u><u> Is The Most Concentrated</u></h2>

<h3>S1:</h3>

M = m/v

= 100ml ÷ 2 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

<h3>S2:</h3>

M = m/v

= 200ml ÷ 5 spoons × 100%

= - 4,000 μg/ppb³

= <u>40% Diluted</u>

<h3>S3:</h3>

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= 300ml ÷ 6 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

<h3>S4: </h3>

M = m/v

= 600ml ÷ 8 spoons × 100%

= - 75,000 μg/ppb³

= <u>75% Diluted</u>

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