when chlorine is added to acetylene tetrachloroethane is formed How many grams of tetrachloroethane are ade if 15 liters of chlo
1 answer:
35.5 g of tetrachloroethane is added if 15 grams of chlorine is used with excess .
A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.
Balanced chemical equation:
→
In your case, 2 moles of chlorine gas are needed to produce 1 mole of tetrachloroethane, which implies that there's a 2:1 mole ratio between the two.
Calculating the mass of tetrachloroethane.
=
X
X
X
=
=
Hence, 35.5 g of tetrachloroethane is added if 15 gram of chlorine is used with excess
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Answer:
- <em>The solution that has the highest concentration of hydroxide ions is </em><u>d. pH = 12.59.</u>
Explanation:
You can solve this question using just some chemical facts:
- pH is a measure of acidity or alkalinity: the higher the pH the lower the acidity and the higher the alkalinity.
- The higher the concentration of hydroxide ions the lower the acidity or the higher the alkalinity of the solution, this is the higher the pH.
Hence, since you are asked to state the solution with the highest concentration of hydroxide ions, you just pick the highest pH. This is the option d, pH = 12.59.
These mathematical relations are used to find the exact concentrations of hydroxide ions:
- pH + pOH = 14 ⇒ pOH = 14 - pH
- pOH = - log [OH⁻] ⇒
Then, you can follow these calculations:
Solution pH pOH [OH⁻]
a. 3.21 14 - 3.21 = 10.79 antilogarithm of 10.79 = 1.6 × 10⁻¹¹
b. 7.00 14 - 7.00 = 7.00 antilogarithm of 7.00 = 10⁻⁷
c. 7.93 14 - 7.93 = 6.07 antilogarithm of 6.07 = 8.5 × 10⁻⁷
d. 12.59 14 - 12.59 = 1.41 antilogarithm of 1.41 = 0.039
e. 9.82 14 - 9.82 = 4.18 antilogarithm of 4.18 = 6.6 × 10⁻⁵
From which you see that the highest concentration of hydroxide ions is for pH = 12.59.
Answer:
<h3>The answer is 235.29 mL</h3>Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question.
density = 0.017 g/mL
mass = 4 g
We have
We have the final answer as
<h3>235.29 mL</h3>Hope this helps you