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Umnica [9.8K]
3 years ago
6

Write an equation that shows the formation of a copper (I) ion from a neutral copper atom

Chemistry
2 answers:
e-lub [12.9K]3 years ago
7 0

<u>Answer:</u> The equation is written below.

<u>Explanation:</u>

Copper is the 29th element of the periodic table having electronic configuration of [Ar]3d^{10}4s^1

When an atom looses an electron to form positive ion, it is called an oxidation reaction.

Copper will loose 1 electron to form +1 ion. The equation for the formation of copper (I) ion from neutral copper atom follows:

Cu\rightarrow Cu^++1e^-

Hence, the equation is written above.

kumpel [21]3 years ago
5 0
Cu ----> Cu(+) + 1 e-
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A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
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Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

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Explanation:

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Answer:

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Explanation:

The image for the question is attached

Solution

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b)

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