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Umnica [9.8K]
3 years ago
6

Write an equation that shows the formation of a copper (I) ion from a neutral copper atom

Chemistry
2 answers:
e-lub [12.9K]3 years ago
7 0

<u>Answer:</u> The equation is written below.

<u>Explanation:</u>

Copper is the 29th element of the periodic table having electronic configuration of [Ar]3d^{10}4s^1

When an atom looses an electron to form positive ion, it is called an oxidation reaction.

Copper will loose 1 electron to form +1 ion. The equation for the formation of copper (I) ion from neutral copper atom follows:

Cu\rightarrow Cu^++1e^-

Hence, the equation is written above.

kumpel [21]3 years ago
5 0
Cu ----> Cu(+) + 1 e-
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Drag the tiles to the correct boxes. Not all tiles will be used. The oxidation number of oxygen is -2, and that of chlorine is -
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<u>Answer:</u>

<em>That oxidation number of chlorine is -1 while that of oxygen is -2</em>

<u>Explanation:</u>

When it comes to manganese chloride to stabilize the chlorine Ion. Two manganese ions shall be required. Hence the formula for the compound becomes M_nCl_2 while the formula for manganese (iv) chloride will be M_nCl_4 similarly.

When oxygen and magnesium oxide is considered the Two ions of Manganese will satisfy to ions of oxygen. Which cancels and becomes M_nO while for manganese (iv) oxide  the formula becomes M_nO_2.

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Misha Larkins [42]

Explanation:

Moles of N2 = 35.0g / (28g/mol) = 1.25mol

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3 years ago
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