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3 years ago

Need help answer to this? n^2-5=-4????????

Mathematics

1 answer:

dalvyx [7]3 years ago

8 0

The answer is n= -1.

Hope this helps

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Is the product 1.23 x 8 greater than or less than 8? Explain.

PIT_PIT [208]

its greater, even if it has the slightest number over 1, such as 1.00000000001

it would still be greater, hope this helps

3 0

3 years ago

Read 2 more answers

What is the sum of the distances of R to Q and P to Q?

Shalnov [3]

The sum of the distances of R to Q and P to Q is 9 units.

Solution:

Given points are P(–3, 6), Q(3, 6) and R(3, 3).

Distance between two points formula:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance from R to Q:

Here $x_1=3, y_1=3, x_2=3, y_2=6$

Substitute these in the given formula, we get

Distance = $\sqrt{(3-3)^2+(6-3)^2}$

$=\sqrt{0+9}$

= 3 units

Distance from R to Q is 3 units.

Distance from P to Q:

Here $x_1=-3, y_1=6, x_2=3, y_2=6$

Substitute these in the given formula, we get

Distance = $\sqrt{(3-(-3))^2+(6-6)^2}$

$=\sqrt{36+0}$

= 6 units

Distance from P to Q is 6 units.

Sum of the distances = 3 + 6 = 9 units

Hence the sum of the distances of R to Q and P to Q is 9 units.

4 0

4 years ago

Evaluate x=3 for 2x<br> x2<br> 1x<br> x1<br> 12x

Law Incorporation [45]

Answer:

Step-by-step explanation:

it's the same both ways. It's still 2 x 3 = 6

I hope this is correct

4 0

3 years ago

A photo of a painting has a scale of 3 inches = 2 feet. If the photo is 7.5 inches long, how many feet long is the painting?

elixir [45]

The painting is 60 inches long

3 0

3 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 160

Salsk061 [2.6K]

Answer:

It would take 75.8 minutes for the element to decay to 2 grams.

Step-by-step explanation:

The number of grams of element x, after t minutes, is given by the following equation:

$X(t) = X(0)(1-r)^{t}$

In which X(0) is the initial amount and r is the decay rate.

There are 160 grams of Element X

This means that X(0) = 160.

$X(t) = X(0)(1-r)^{t}$

$X(t) = 160(1-r)^{t}$

Half life of 12 minutes.

This means that X(12) = 0.5*X(0) = 0.5*160 = 80. So

$X(t) = 160(1-r)^{t}$

$80 = 160(1-r)^{12}$

$(1 - r)^{12} = 0.5$

$\sqrt[12]{(1 - r)^{12}} = \sqrt[12]{0.5}$

$1 - r = 0.9438$

$X(t) = 160(1-r)^{t}$

$X(t) = 160(0.9438)^{t}$

How long would it take for the element to decay to 2 grams?

This is t for which X(t) = 2. So

$X(t) = 160(0.9438)^{t}$

$2 = 160(0.9438)^{t}$

$(0.9438)^{t} = \frac{2}{160}$

$\log{(0.9438)^{t}} = \log{\frac{2}{160}}$

$t\log{0.9438} = \log{\frac{2}{160}}$

$t = \frac{\log{\frac{2}{160}}}{\log{0.9438}}$

$t = 75.8$

It would take 75.8 minutes for the element to decay to 2 grams.

6 0

3 years ago