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Whitepunk [10]
3 years ago
10

Write the numbers in order from least to greatest

Mathematics
1 answer:
spayn [35]3 years ago
4 0

C.) -4, -7/5, 1/6, 1.6, \sqrt{6}


\sqrt{6} = 2.45

1.6

1/6 = 0.167

-7/5 = -1.4

-4

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Dorji thought of a number. He first multiplied the number by 3 and then subtracted 12
jeyben [28]

Answer

The answer is 24

Step-by-step explanation

  • 24 x 3 = 72
  • 72 - 12 = 60
  • 60/6 = 10
  • 10 - 4 = 6
6 0
3 years ago
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
Which statement must be true about line TU?
just olya [345]
Line tu is parallel to rs
5 0
3 years ago
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Jim provides photos for two online sites: site A and site B. Site A pays $0.85 for every photo Jim provides. The amount in dolla
yarga [219]
We can use the same equation to figure out with only substituting the amount he was paid per photo.

Site A    y = $0.85x      =  $0.85(5)  =  $4.25
Site B    y = $0.40x      =  $0.40(5)  =  $2.00

We can see that Jim was paid $2.25 more at site A than Site B.
6 0
3 years ago
Read 2 more answers
The Smith house payments are 800$ per month. What percent of their combined take home pay goes for the house payments? (96,169 i
Nat2105 [25]
If $96,169 is their combined pay in one year then consider this...
800x12=9,600

Simplify 96,169 to 96,000...

Divide 96,000 by 9,600 = 10.0
then pretend we had divided 96,100 by 9,600 then your answer would be 10.01
5 0
3 years ago
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