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spayn [35]
3 years ago
6

Does there exist 2 distinct prime numbers such that their product is a square number?​

Mathematics
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

NO.

Step-by-step explanation:

If the 2 prime numbers are odd then the product cannot be a square number because the only factors are the original prime numbers.  If one of the prime numbers is 2 then the product will be an even number , but again the only factors will be 2 and the other prime number.

So the answer is No.

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Write an equation in point slope form for each line<br> Slope is 3 and (-2,-1) is on the line
elena-14-01-66 [18.8K]

Answer:

\huge  \blue{y + 1 = 3(x + 2) } \\

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

From the question we have the final answer as

y + 1 = 3(x + 2)

Hope this helps you

6 0
3 years ago
Simplify.
Dafna1 [17]

Answer:

A) 7x^3 + 13x^2 + 8x + 9

Step-by-step explanation:

(3x^2 + 2x + 7x^3) + (10x^2 + 6x + 9)

I like to line them up vertically

7x^3 +3x^2 + 2x

+       (10x^2 + 6x + 9)

-----------------------------------

7x^3 +13x^2 +8x +9

4 0
3 years ago
Read 2 more answers
2/3 plus negative 1/3
vovikov84 [41]

2/3 + (-1/3) = 2/3 - 1/3 = 1/3

3 0
3 years ago
Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2
ivanzaharov [21]

Answer:

اhello : tan θ = - 12/5

Step-by-step explanation:

tan θ = sin θ / cos θ .... (*)

(cosθ)² + (sinθ)² = 1   ... (**)

theta is in quadrant 2 : cosθ ≤ 0

Substitute sinθ = 12/13  into (**) and solve for cosθ :

(cosθ)² + (12/13)² = 1  

(cosθ)²  = 1   - 144/169

(cosθ)²  = 25/169

cosθ = - 5 /13  because  cosθ ≤ 0

by (*) : tan θ = (12/13)/ (-5/13) = (12/13) ×(-13/5)

tan θ = - 12/5

3 0
3 years ago
Which inequality has the solution n &lt; 5?<br>i really need this help
katrin2010 [14]

Answer:

1000 and 9000 and 40

Step-by-step explanation:

5 0
2 years ago
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