Does there exist 2 distinct prime numbers such that their product is a square number?

Mathematics

1 answer:

satela [25.4K]3 years ago

5 0

Answer:

NO.

Step-by-step explanation:

If the 2 prime numbers are odd then the product cannot be a square number because the only factors are the original prime numbers. If one of the prime numbers is 2 then the product will be an even number , but again the only factors will be 2 and the other prime number.

So the answer is No.

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Step-by-step explanation:

$f(x) =4x^3-8x^2+ax+b$ has a factor $2x-1$ and

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