Answer:
1 or 5
Step-by-step explanation:
Given the function h(x)=(2x−2)(x−5)
The zeros of h(x) are the values of x for which h(x)=0
h(x)=(2x−2)(x−5)=0
Note that if a.b=0, either a=0 or b=0.
Appying the above,
If (2x−2)(x−5)=0
Then:
2x−2=0 or x-5=0
2x=2 or x=5
x=1 0r 5
The zeroes of h(x) as defined are 1 or 5.
Answer:
x = -3/16
Step-by-step explanation:
6x + 5x - 25 = -5x - 28
11x - 25 = -5x - 28
Add 5x to both sides.
16x - 25 = -5x + 5x - 28
16x - 25 = -28
Add 25 to both sides.
16x - 25 + 25 = -28 + 25
16x = -3
Divide both sides by 16
16/16 = 1
-3/16
x = -3/16
Answer:
Step-by-step explanation:
Answer is B hope this helps
