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Elodia [21]
3 years ago
9

Bailey buys a car for $18,000 and it has a depreciation value of 16% per year after 3

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

$10668.67

Step-by-step explanation:

If the car value goes down 16% each year, after the first year, it will be worth 1520.

The next year, it will be worth $12700.80

After the third year, the car will be worth $10,668.67

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Eva is picking fruit at a farm. The fees are $5 for entry to the farm, $2.50 per pound of blueberries, and $2 per pound of apple
olasank [31]

Answer:

The required expression is: y = 5 + 2.50b + 2a

Step-by-step explanation:

Given

Entry = \$5

Blueberry = \$2.50

Apple = \$2

Required

Write an expression for this scenario

If 1 pound of blueberry cost $2.50

then b pounds = 2.50 * b

If 1 pound of apple cost $2

then a pounds = 2 * a

The required expression (y) is then calculated as

y = Entry\ Fee + Blueberry = Apple

y = 5 + 2.50 * b + 2 * a

y = 5 + 2.50b + 2a

Hence, the required expression is: y = 5 + 2.50b + 2a

8 0
3 years ago
Find the equation is standard form, of the line passing through he points (2,-3) and (4,2)
Simora [160]

The point slope formula:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

(2,\ -3)\to x_1=2,\ y_1=-3\\(4,\ 2)\to x_2=4,\ y_2=2

Substitute:

m=\dfrac{2-(-3)}{4-2}=\dfrac{5}{2}=2.5\\\\y-(-3)=2.5(x-2)\\\\y+3=2.5x-5\ \ \ \ |+5\\\\y+8=2.5x\ \ \ \ \ \ |-y\\\\2.5x-y=8\ \ \ \ \ |\cdot2\\\\\boxed{5x-2y=16}

5 0
3 years ago
Point V lies between points U and W on Line segment U W.
Nutka1998 [239]

Answer:

The correct answer is (d) 36 units.

Step-by-step explanation:

Just took the test on edge :)

5 0
3 years ago
Read 2 more answers
Sophia's school has 23 classrooms. Each classroom has 10 tables. How many tables are there in the school? ​
amid [387]
If there is 23 classrooms and each has 10 then you would have to times 23 by 10 - 23x10=230
4 0
3 years ago
Read 2 more answers
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0
3 years ago
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