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mamaluj [8]
4 years ago
8

Find the area of a triangle with a base 24 feet long and a height of 12 feet

Mathematics
2 answers:
sleet_krkn [62]4 years ago
3 0

Answer:

base times height divided by two. Answer is 144 ft

tresset_1 [31]4 years ago
3 0

The Area would be 144ft^{2}

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Find which inequality statement is correct. A café used 15.75 pounds of flour on Monday and 15.57 pounds of flour on Tuesday. Wh
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Will give brainiest In △ABC, angle bisectors
EleoNora [17]

Answer:

m\angle CAB=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=25\dfrac{5}{7}^{\circ}

Step-by-step explanation:

AK is angle A bisector, then

m\angle BAK=m\angle KAC=x^{\circ}

BL is angle B bisector, then

m\angle ABL=m\angle CBL=y^{\circ}

Consider triangle ABL. The sum of the measures of all interior angles in this triangle is 180^{\circ}, then

m\angle BAL+m\angle ALB+m\angle LBA=180^{\circ}\\ \\2x+2y+y=180\\ \\2x+3y=180

Consider triangle ABK. In this triangle,

m\angle AKB=180^{\circ}-2x^{\circ} \ [\text{Supplementary angles}]

The sum of the measures of all interior angles in this triangle is 180^{\circ}, then

m\angle BAK+m\angle AKB+m\angle KBA=180^{\circ}\\ \\x+(180-2x)+2y=180\\ \\2y-x=0

Hence,

x=2y\\ \\2(2y)+3y=180\\ \\4y+3y=180\\ \\7y=180\\ \\y=\dfrac{180}{7}=25\dfrac{5}{7}\\ \\x=\dfrac{360}{7}=51\dfrac{3}{7}

Find the measures of the triangle ABC:

m\angle CAB=2x^{\circ}=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=2y^{\circ}=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=180^{\circ}-102\dfrac{6}{7}^{\circ}-51\dfrac{3}{7}^{\circ}=25\dfrac{5}{7}^{\circ}

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