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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer: The correct answer would be V=343cm³
Answer:
-6-b
Step-by-step explanation:
4(1-2b)+7b-10
Multiply what's in parantheses
4(1)=4
4(-2b)=-8b
4-8b+7b-10
Combine like terms
4-10 -8b+7b
-6-b
Hope this helps :)
Answer:
1. 35
2. 145
3. 55
4. 90
5. 145
Step-by-step explanation:
1. 35: angle 1 and 2 are a linear pair (meaning it is in one line and adds to 180). Since we know angle 2 is 145, ∠1 = 180 - 145
∠1 = 35
2. 145: ∠7 = ∠2 because they are alternate angles and alternate angles are equal
3. 55: ∠7 = ∠5 + ∠4 because vertically opposite angles are equal. We know that ∠5 = 90, hence ∠4 would equal 145 - 90 = 55
4. ∠5 = 90. It is given
5. 145: ∠9 = ∠2 because they are vertically opposite
Answer:
The PERIMETER P is the distance around the rectangle.
Let's call the width of the rectangle W and the length of the rectangle L.
As you go around the edge there two equal lengths and two equal widths.
The formula for the perimeter of a rectangle is P=2*L+2*W.
P=2L%2B2W
Substitute 290 for P and 62 for the width.
290=2L%2B2%2862%29
Solve for L.
290=2L%2B2%2862%29
290=2L%2B124
290-124=2L
2L=166
L=83
The equation L=83 means that the length is 83 cm.
CHECK your work.
2(62)+2(83) = 124+166 = 290cm.
The length of the rectangle is 83cm.
