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frutty [35]
3 years ago
13

Word form for 6,392,094,003

Mathematics
1 answer:
Burka [1]3 years ago
5 0

Six billion, three hundred ninety-two million, ninety-four thousand and three.

( If it's wrong, please comment about it. )

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A researcher is interested in estimating the mean weight of a semi trailer truck to determine the potential load capacity. She t
Kaylis [27]

Answer: 95% confidence interval = 20,000 ± 2.12\times\frac{1500}{\sqrt{17} }

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

Step-by-step explanation:

Given :

Sample size(n) = 17

Sample mean = 20000

Sample standard deviation = 1,500

5% confidence

∴ \frac{\alpha}{2} = 0.025

Degree of freedom (d_{f}) = n-1 = 16

∵ Critical value at ( 0.025 , 16 ) = 2.12

∴ 95% confidence interval = mean ± Z_{c}\times\frac{\sigma}{\sqrt{n} }

Critical value  at 95% confidence interval = 20,000 ± 2.12\times\frac{1500}{\sqrt{17} }

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

3 0
3 years ago
Can someone help me please
Blizzard [7]

Answer:

Area=76.56 square feet

Step-by-step explanation:

area of a rectangle =base*height = 5ft*8ft= 40 square feet

area of a triangle=(base*height)/2 =(4ft*4ft)/2= 8 square feet

area of a square=base*height =4ft*4ft= 16 square feet

area of a circle =\pi* r^{2}[/tex]=3.14*2^{2}= 12.56 square feet

r = radius

Total area=(40+8+16+12.56)square feet

Total area=76.56square feet

3 0
3 years ago
19810 rounded to the nearest hundred
Cloud [144]
19,810 rounded to the nearest hundred is 19,800.
8 is in the hundreds place, and the number 1 is in front of it.
 
Numbers 1-4 in front of the number make the number stay the same.

Numbers 5-9 in front of the number make the numbers round up one number.
3 0
3 years ago
Read 2 more answers
Two similar prisms have heights 4 cm and 10cm what is the ratio of their surface areas
Slav-nsk [51]
Let k be the scale factor relating two similar prisms P_{1} and P_{2}, such that for corresponding parts of prisms P_{1} and P_{2} (for heights, in particular) we have k= \frac{height\  of \ P_{1} }{height \ of\  P_{2} }. In our case k= \frac{4}{10} = \frac{2}{5}.
For surfaces area we have \frac{Surface \ area \ of \  P_{1} }{Surface \ area \ of \  P_{2}} = k^{2} =( \frac{2}{5} )^{2}= \frac{4}{25}.
So, the right answer is 4:25 (choice B)



4 0
3 years ago
Help me with this please
KiRa [710]
No pongas foto por que no puedo ver y no te puedo responder
7 0
3 years ago
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