All categories

2 years ago

I need big help, what are the step by step math problem and the answer to (18/-2)^2?

Mathematics

2 answers:

Serggg [28]2 years ago

8 0

Hii :))

$\tt \: ( \frac{18}{ - 2} ) ^{2} \\ \tt \: = (- \frac{18}{2} ) ^{2} \\ \tt = \frac{-18 \times -18}{-2 \times -2} \\ = \tt \frac{324}{4} \\ = \boxed{\tt\:81}$

﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋

$\overbrace{ \underbrace{ \sf \: \infty \: Carry \: on \: Learning \: \infty }}$

ᴛʜᴇᴇxᴛʀᴀᴛᴇʀᴇꜱᴛʀɪᴀʟ

sergiy2304 [10]2 years ago

5 0

Answer: 81

( 18 / -2 )^2

( first divide 18 by negative 2. 18/2 is 9, made negative )

( -9 )^2

( 9 squared, so 81 )

81 is the final answer

You might be interested in

Mr grant needs 30 pieces of felt he can buy them in packs of 10 or as single pieces what are the different ways mr

Olin [163]

The correct answer is:

He can buy 3 packs of 10 or 30 single pieces.

Explanation:

He needs 30 pieces. Since they are sold in 10 packs, it would take 30/10 = 3 packs of 10.

Other than this, the pieces are sold as singles. This means he could also buy 30 single pieces.

6 0

2 years ago

How to do this question plz

hjlf

Answer:

$\underline{ \boxed{ \underline{part \: a}}}. \\the \: required \: distance \: a part \: be \to \: \boxed{\underline {\overline{p } =79.23 \: km} } \\ \\ \underline{ \boxed{ \underline{part \: b}}}. \\ the \: bearing \: of \: \boxed{ B } \: \: from \: \boxed{ \underline{A}} \: is \to \boxed{ \underline{324 }\degree }$

Step-by-step explanation:

$\underline{ \boxed{ \underline{part \: a}}}. \\ l et \: the \: required \: distance \: apart \: be \to \: \boxed{ \overline {p}} \\ let \: \boxed{ \angle \: P} \: be \: the \: angle \: of \: seperation \: between \: both \: ships :given \: by \to \\ P = (244 - 180) - (196 - 180 )= (64 -16) = \boxed{48 \degree} \\ if \: ship \: A \: and \: B \: left \: the \: port\: at \: (10:30) \: \\ then \: at \: (14 :00) \: their \: time \: interval \: would \: be \to \\ (14 : 00) - (10 : 30) = \boxed{ 3.5 \: hrs} \\ ship \: \boxed{A }\: distance \: from \: the \: port =( v \times t) = (30 \times 3.5) = \boxed{105 \: km} \\ ship \: \boxed{B }\: distance \: from \: the \: port =( v \times t) = (24 \times 3.5) = \boxed{84\: km} \\n ow........we \: cant \: do \: much \: if \: their \: are \: no \: angles \: to \: work \: with \to \\ applying \:t he \: cosine \: rule : we \: have \to \\ \cos(P) = \frac{ {a}^{2} + {b}^{2} - \overline{{p}^{2} } }{2(ab)} \\ {a}^{2} + {b}^{2} - \overline{{p}^{2} } = 2(ab) \cos(P) \\ \overline{{p}^{2} } = {a}^{2} + {b}^{2} - \{2(ab) \cos(P) \} \\ \overline{{p}^{2} } = {84}^{2} + {105}^{2} - \{2(84)(105) \cos(48 \degree) \} \\\overline{{p}^{2} } = 18,081 - 11,803.463897 \\ \overline{{p}^{2} } = 6,277.536103 \\ \overline{p } = \sqrt{6,277.536103} \\ \boxed{\underline {\overline{p } =79.23 \: km} } \\ \\ \underline{ \boxed{ \underline{part \: b}}}. \\ to \: sove \: this : we \: first \: find \: angle \: \angle \: B : by \: applying \to \\ \frac{ \sin(B) }{b} = \frac{ \sin(P) }{p} \\ p \ast \sin(B) = b \ast \sin(P) \\ B = \sin {}^{ - 1} ( \frac{ b \ast \sin(P)}{p} ) \\ B = \sin {}^{ - 1} ( \frac{ 105 \times \sin(48 \degree)}{79.230903712} ) \\ \\ B = \sin {}^{ - 1} ( \frac{ 78.030206678}{79.230903712} ) \\ \\ B = \sin {}^{ - 1} (0.9848455971) \\ \boxed{B = 80 \degree} \\ hence \ : the \: bearing \: of \: \boxed{ B } \: \: from \: \boxed{ \underline{A}} \: is \to \\ 360 - \{180 - (80 + 48 + 16) \} \\ 360 -(180 - 144 )\\ 360 -36 = \boxed{324 \degree }$

♨Rage♨

7 0

2 years ago

The value of Q is given by the relation Q = 17m. If Q and m are integers with Q greater than 150 and less than 160, then which o

zloy xaker [14]

Answer: Value of m = 9

Step-by-step explanation:

Given that the relationship between Q and m is;

Q = 17m

Make m the subject of formula

M = Q/17

If Q is greater than 150 and less than 160, then, let assume that

Q = 151, then

M = 151/17

M = 8.88

If Q = 159

M = 159/17

M= 9.35

Since m ranges from 8.88 to 9.35, the value of m = 9

6 0

2 years ago

Determine the constant that must be added to the given expression to complete the square and express the resulting trinomial as

erma4kov [3.2K]

Constant:9
Expression: (x-3)^2

8 0

3 years ago

if you have 200 ¨toys¨ and your 2 brother stills 40 each and your mom throws away 90 how many ¨toys¨ do you have left

Y_Kistochka [10]

Answer:

you have 30 left

Step-by-step explanation: use a calculator bruh

5 0

3 years ago

Read 2 more answers