Answer:
U = 25 J
Explanation:
The energy in a set of charges is given by
U = 
in this case we have three charges of equal magnitude
q = q₁ = q₂ = q₃
with the configuration of an equilateral triangle all distances are worth
d = a
U = k ( 
)
we substitute
15 = k q² (3 / a)
k q² /a = 5
For the second configuration a load is moved to the measured point of the other two
d₁₃ = a
The distance to charge 2 that is at the midpoint of the other two is
d₁₂ = d₂₃ = a / 2
U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})
U = k q² ( 
)
U = (kq² /a) 5
substituting
U = 5 5
U = 25 J
Answer:
The combined mass of the two particles is completely transformed into energy (photons). This process is called matter-antimatter annihilation.
Explanation:
Explanation:
Net force on the car= mass of the car × acceleration
F=1×10^3×4.5
=4.5×10^3 N
Answer:
The resulting velocity of the ball after it hits the racket was of V= 51.6 m/s
Explanation:
m= 55.6 g = 0.0556 kg
t= 2.8 ms = 2.8 * 10⁻³ s
F= 1290 N/ms * t - 330 N/ms² * t²
F= 1024.8 N
F*t= m * V
V= F*t/m
V= 51.6 m/s
Answer:
The magnitude of acceleration should be increasing.
Velocity is positive as the mass is moving towards the maximum positive displacement. Velocity would be decreasing. Acceleration is negative as velocity is decreasing. Additionally, the magnitude of acceleration would be increasing (becomes more negative.)
Explanation:
As the mass in this question moves upwards, the displacement of this mass is becoming more positive. Hence, the velocity of this mass would be positive.
In a simple harmonic motion, velocity is:
- maximized at the equilibrium position (where displacement is
,) and - when displacement is maximized.
The mass in this question is moving from displacement (where velocity is maximized) towards maximum displacement (where velocity is .) Thus, the velocity of the mass would be decreasing.
Since the velocity of this mass is decreasing, the acceleration of this mass would be negative. In a simple harmonic motion, acceleration is:
- at the equilibrium position, and
- maximum when displacement is maximized, but opposite to the direction of displacement.
The mass in this question is moving from the equilibrium position (where acceleration is ) towards maximum displacement (where acceleration is most negative.) Thus, the magnitude of the acceleration of this mass would be increasing, and the acceleration of the mass would become more negative.
