Because Helium fusion in a shell outside the core generates enough thermal pressure to push the upper layers outward.
Answer and Explanation:
KUIPER BELT : The Kuiper belt is on the name of the scientist kuiper .It is the largest structure of the solar system its inner edge is about 30 AU from the Sun. The thickness of the kuiper belt is about 10 AU. It contains comets and other icy bodies
OORT CLOUD : The name of this cloud is one the name of a scientist Jhon oort. It is a theoretical cloud and mainly consist icy bodies it far away from the Sun. Its structure is spherical in nature and mostly contain ice water amonia methane
Answer:
Va = 5000 m / 3600 s = 1.39 m/s
(Va - Vb) 60 = 10
Vb = Va - .167 = 1.22 m/s
(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap
.17 T = 4200 Π
T = 24700 Π time for A to again catch B
N = 1.39 * 24700 Answer:
Va = 5000 m / 3600 s = 1.39 m/s
(Va - Vb) 60 = 10
Vb = Va - .167 = 1.22 m/s
(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap
.17 T = 4200 Π
T = 24700 Π time for A to again catch B
N = 1.39 * 24700 Π / (4200 Π) = 8.2 laps
A will make 8 but not 9 rounds before catching B
Answer:
a)
b) 
c)
Explanation:
Magnitude of charges 
Distance 
Generally the equation for Net Force is mathematically given by
For First Drawing


For second Drawing

For Third Drawing



Answer:
![(a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A](https://tex.z-dn.net/?f=%28a%29%5C%20F_%7BNo%7D%20%3D%20%5BP_%7BNo%7D%20-%20%5Cfrac%7BP_%7Barea%7D%7D%7B2%7D%5D%2A%20A)

Explanation:
Given
---- Altitude of container in Denver
-- Surface Area of the container lid
--- Air pressure in Denver
--- Air pressure in New Orleans
<em>See comment for complete question</em>
Solving (a): The expression for 
Force is calculated as:

The force in New Orleans is:

Since the inside pressure is half the pressure at sea level, then:

Where
--- Standard Pressure
Recall that:

This gives:
![F_{No} = [P_{No} - \frac{P_{area}}{2}]* A](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5BP_%7BNo%7D%20-%20%5Cfrac%7BP_%7Barea%7D%7D%7B2%7D%5D%2A%20A)
Solving (b): The value of 
In (a), we have:
![F_{No} = [P_{No} - \frac{P_{area}}{2}]* A](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5BP_%7BNo%7D%20-%20%5Cfrac%7BP_%7Barea%7D%7D%7B2%7D%5D%2A%20A)
Where



So, we have:
![F_{No} = [100250 - \frac{101000}{2}] * 0.0155](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5B100250%20-%20%5Cfrac%7B101000%7D%7B2%7D%5D%20%2A%200.0155)
![F_{No} = [100250 - 50500] * 0.0155](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5B100250%20-%2050500%5D%20%2A%200.0155)

