What is the name of the process that puts adp and phosphate together to form atp

Physics

1 answer:

lorasvet [3.4K]3 years ago

7 0

ADP has 2 phosphate groups, and when another phosphate group is added it becomes ATP.

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If a Ferrari, with an initial velocity of 10 m/s,

soldier1979 [14.2K]

Acceleration at 50m/sec² : means every second the velocity increases by 50 m/sec. In 3 seconds the velocity increases by 150 m/s. So total will be 160 m/sec.

the formula is

 V = final velocity = U initial velocity + acceleration a * time duration t

 V = 10 m/s + 50 m/sec² * 3 sec = 160 m/sec

6 0

2 years ago

All atoms of the element potassium have 19 protons. One of the most stable types of potassium atoms has the mass number 39. How

nydimaria [60]

For atoms in the periodic table, the given mass number is the sum of the number of the protons (also called the atomic number) and the number of the neutrons inside its nucleus. Mathematically,
mass number = atomic number + number of neutrons
Substituting,
39 = 19 + n
n = 39 - 19 = 20
Therefore, the answer is not found in the choices.

7 0

2 years ago

Read 2 more answers

Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$x$ is the horizontal distance traveled by the venom

$V_{o}=3.10 m/s$ is the venom's initial speed

$\theta=47\°$ is the angle

$t$ is the time since the venom is spitted until it hits the ground

y-component:

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.44 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

$0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}$ (3)

Rewritting (3):

$-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0$ (4)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula: