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alukav5142 [94]
3 years ago
9

What is the name of the process that puts adp and phosphate together to form atp

Physics
1 answer:
lorasvet [3.4K]3 years ago
7 0
<span>ADP has 2 phosphate groups, and when another phosphate group is added it becomes ATP. </span><span />
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C.) The Distance DH = 1.5 lambda

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Three uniform spheres of radius 2R, R, and 3R are placed in a line, in the order given, so their centers are lined up and the sp
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Answer:

x = 2.33 R from the center of mass of the smallest sphere.

Explanation:

Due to the symmetry of the spheres, the center of mass of any of them, is located just in the center of the sphere.

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By definition, the x-coordinate of the center of mass of a set of discrete masses m₁, m₂, m₃, can be calculated as follows:

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In this case, we need to get the coordinates of the center of mass of each sphere:

If we place the spheres in such a way that the center of the first sphere has the x-coordinate equal to its radius (so it is just touching the origin), we will have:

x₁ = 2*R

For the second sphere, the center will be located at a distance equal to the diameter of  the first sphere plus its own radius, as follows:

x₂ = 4*R + R = 5*R

Finally, for the third sphere, the center will be located at a distance equal to the diameter of  the first sphere, plus the diameter of the second sphere,  plus its own radius, as follows:

x₃ = 4*R + 2*R + 3*R = 9*R

We can calculate the mass of each sphere (assuming that all are from the same material, with a constant density), as the product of the density and the volume:

m = ρ*V

For a sphere, the volume can be calculated as follows:

\frac{4}{3} *\pi *(r)^{3}

So, we can calculate the masses of the spheres, as follows:

m₁ = ρ*\frac{4}{3} *\pi *(2r)^{3}

m₂ = ρ*\frac{4}{3} *\pi *(r)^{3}

m₃ = ρ*\frac{4}{3} *\pi *(3r)^{3}

The total mass can be calculated as follows:

M= ρ*\frac{4}{3} *\pi * (8*r³ + r³ + 27*r³) =ρ*\frac{4}{3} *\pi * 36*r³

Replacing by the values, and simplifying common terms, we can calculate the x-coordinate of the center of mass of the system as follows:

Xcm = \frac{m1*x1+m2*x2+m3*x3}{m1+m2+3}

Xcm = \frac{(8*R^{3} *2*R)+(R^{3}*(5*R))+27*R^{3}*(9*R))}{36*R^{3} }=\frac{264*R^{4} x}{36*R^{3}} = 7.33 R

As the x-coordinate of the center fof mass of the entire system is located at 7.33*R from the origin, and the center of mass of the smallest sphere is located at 5*R from the origin, the center of mass of the system is located at a distance d:

d = 7.33*R - 5*R = 2.33 R

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