Answer:
Step-by-step explanation:
tell me the question ?? did not say the question ok ??
The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial
has solutions
, then you can factor it as

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

But this is a fourth-degree polynomial.
Easy, subsitute a point
we see it goes through (0,4)
so subsitte 0 for x and see if we get 4
4^0=1, nope
4^0-3=1-3=-2, nope
4^0+3=1+3=4, yep
4^(0+3)=4^3=64, noe
answer is 3rd option
f(x)=4^x+3
-16 + 3n = -(8 + 5n)
The - sign outside the parentheses acts as a -1, and so it is distributed to each term in the parentheses.
-16 + 3n = -8 - 5n
+16
3n = 8 - 5n
+5n
8n = 8
/8
n = 1