SOLUTIONS
Given: Assume y is the population

The town grow at the rate of 30 people per year.


(A) The population predicted to be in 2030 will be

(B) so when y = 15000, find t
The equal of x+7=26 so it’s definitely (a)
(p-8-m)/(-1+p)=1 1/9;p=1 7/8
(p+1)/(p+8+m)=1 1/9;p=1 7/8
1/(8+m)=10/9;p=15/8
that's as far as it can be solved