The force exerted by the magnetic in terms of the magnetic field is,
![F\propto B](https://tex.z-dn.net/?f=F%5Cpropto%20B)
Where B is the magnetic fied strength and F is the force.
Thus, if the magnetic A has twice magnetic field strength than the magnet B,
Then,
![B_A=2B_B](https://tex.z-dn.net/?f=B_A%3D2B_B)
Thus, the force exerted by the magnet B is,
![\begin{gathered} F_B\propto B_B \\ F_B\propto\frac{B_A}{2} \\ F_B=\frac{F_A}{2} \\ F_B=\frac{100}{2} \\ F_B=50\text{ N} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20F_B%5Cpropto%20B_B%20%5C%5C%20F_B%5Cpropto%5Cfrac%7BB_A%7D%7B2%7D%20%5C%5C%20F_B%3D%5Cfrac%7BF_A%7D%7B2%7D%20%5C%5C%20F_B%3D%5Cfrac%7B100%7D%7B2%7D%20%5C%5C%20F_B%3D50%5Ctext%7B%20N%7D%20%5Cend%7Bgathered%7D)
Thus, the force exerted by the magnet B on magnet A is 50 N.
The force exerted by the magnet A exerts on the magnet B is exactly 100 N as given.
Hence, the option B is the correct answer.
During that period of time, the bird's displacement was 4 km east. So its velocity was (4km east)/(11hrs). That's 0.36 km/hour east. (rounded)
Answer:
marblebrainiest plz\c cmarble
Explanation: