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shutvik [7]
3 years ago
13

Which of the following does NOT describe the conversion of potential to kinetic energy? Question 12 options:

Physics
1 answer:
Marianna [84]3 years ago
6 0

The option “The sum emitting light energy” does not describe the conversion of potential energy to kinetic energy.

Answer: Option A

<u>Explanation: </u>

The potential energy, the object's energy at rest while the kinetic energy is the energy the object in motion. So among the options given, a rocket leaving the Earth's atmosphere consists of conversion of potential energy as the thrusting force to kinetic energy of the movement of the rocket to space.

Similarly the stretching of rubber band is a form of elastic potential energy and when it is released, the band will vibrate which will be the converted kinetic energy.

Also, the avalanche is the falling of ice berg which were once in rest, so the potential energy of the ice berg will get converted to kinetic energy during avalanche.

The option that is the sun emitting light does not convert potential to kinetic energy, instead it converts potential to light energy.

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8 0
2 years ago
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3 years ago
A sled is moving at a constant speed down a surface inclined at 45.0° with the horizontal and travels 30 meters in 4 seconds. Ca
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5 0
3 years ago
Consider an air parcel at latitude = 18◦N, moving northward (conserving absolute vorticity), with initial relative vorticity = 5
mariarad [96]

Answer:

relative vorticity is  -0.868 × 10^{-5} s-1

Explanation:

given data

air parcel at latitude = 18◦N

relative vorticity = 5.8 × 10^−5 s−1

to find out

relative vorticity

solution

we will apply here conservation of vorticity that is

ζ + f = constant

we know ζ initial = 2Ωsin(5π/18)

and  f initial = 5.8 × 10^{-5}

and f final =  2Ωsin(π/18)

and here angular frequency Ω = 0.7272 × 10^{-4} s-1

its mean

ζ initial -  ζ final = f final - f initial

so

ζ final =  ζ initial - f final + f initial

ζ final =  - 2Ωsin(5π/18) + ( 2Ωsin(π/18) +  5.8 × 10^{-5}  )

ζ final =  - 2(0.7272 × 10^{-4}) sin(5π/18) + ( 2(0.7272 × 10^{-4})sin(π/18) +  5.8 × 10^{-5}  )

ζ final = -0.868 × 10^{-5} s-1

so relative vorticity is  -0.868 × 10^{-5} s-1

6 0
3 years ago
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