Answer:
the speed of the bullet before striking the block is 302.3 m/s.
Explanation:
Given;
mass of the bullet, m₁ = 28.3 g = 0.0283 kg
mass of the wooden block, m₂ = 5004 g = 5.004 kg
initial velocity of the block, u₂ = 0
final velocity of the bullet-wood system, v = 1.7 m/s
let the initial velocity of the bullet before striking the block = u₁
Apply the principle of conservation of linear momentum to determine the initial velocity of the bullet.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
0.0283u₁ + 5.004 x 0 = 1.7(0.0283 + 5.004)
0.0283u₁ = 8.5549
u₁ = 8.5549 / 0.0283
u₁ = 302.3 m/s
Therefore, the speed of the bullet before striking the block is 302.3 m/s.
The answer is 6 i no this because im in high school this app is for high schoolers now I'll answer more. of ur questions if u make them have more points now u shouldn't play this game because ur prob in elementary but any ways the answer is 6
Explanation:
ω = 30 rev × (2π rad/rev) / (6 sec)
ω = 10π rad/s
ω ≈ 31.4 rad/s
A) Water freezing
This is called the process of turning water as a liquid to its solid form which is ice.
Ice is almost together as one unlike liquid. This is why the molecules are more orderly.
The process of freezing is exothermic which means the heat has to be removed in the process.
First find the time it takes for the ball to reach the ground using the vertical component of its position vector:
Meanwhile, the horizontal component of the ball's position vector is
After about 4.52 s, the ball has traveled a horizontal distance of
which you would round to 200 m, so the answer is B.
