When rounding to the nearest ten, the greatest whole number that rounds to 270 is

Which number goes first, second and in third place in a number line? The numbers are 0.666666, 0.33, 0.6

hodyreva [135]

0.33 -0.6 -0.666666 that's how they would go

6 0

3 years ago

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helppp please ???????? i don’t understand

Vedmedyk [2.9K]

Answer:

should be -8

Step-by-step explanation:

when reflecting over the x-axis, y changes from positive to negative or negative to positive. x stays the same.

when reflecting over the y-axis, x changes from positive to negative or negative to positive. y stays the same.

4 0

3 years ago

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Please answer correctly Option d is x=10 the picture was to big to include that option

Sladkaya [172]

Answer:

The answer is x = 10.

Step-by-step explanation:

Use the pythagorean theorem. A would be 6, B would be 8, and C would be solved by the product of that.

7 0

3 years ago

during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak

STatiana [176]

<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

$f(t)=-16t^{2}+64t+4$

Where,

$a=-16\\b=64\\c=4$

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

$f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0$

Using the quadratic equation:

$\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615$

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

$f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0$

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

3 0

4 years ago

The function f(x)=/-x is shown on the graph

Katyanochek1 [597]

we know that

For the function shown on the graph

The domain is the interval--------> (-∞,0]

$x\leq0$

All real numbers less than or equal to zero

The range is the interval--------> [0,∞)

$y\geq 0$

All real numbers greater than or equal to zero

so

Statements

case A) The range of the graph is all real numbers less than or equal to $0$

The statement is False

Because the range is all numbers greater than or equal to zero

case B) The domain of the graph is all real numbers less than or equal to $0$

The statement is True

See the procedure

case C) The domain and range of the graph are the same

The statement is False

Because the domain is all real numbers less than or equal to zero and the range is is all numbers greater than or equal to zero

case D) The range of the graph is all real numbers

The statement is False

Because the range is all numbers greater than or equal to zero

therefore

the answer is

The domain of the graph is all real numbers less than or equal to $0$

8 0

3 years ago

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