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Novosadov [1.4K]
3 years ago
8

Refer the homework helper what is the diffrence between the greatest green bean weight and the least green bean weight?

Mathematics
1 answer:
QveST [7]3 years ago
6 0

Answer:

3/4 pounds

Step-by-step explanation:

Given the weights :

weight of beans 1/4 pound, 1/2 pound, 3/4. pound and 1 pound.​

Greatest weight = 1 pound

Least weight = 1/4 pound

Difference = greatest weight - Least weight

Difference = (1 - 1/4) pound

Difference in weight = 3/4 pounds

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Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
What is the value of this expression <img src="https://tex.z-dn.net/?f=%20-8%5E%7B3" id="TexFormula1" title=" -8^{3" alt=" -8^{3
BARSIC [14]
-8^3 = (-8)(-8)(-8) = -512
6 0
3 years ago
Read 2 more answers
5 x 10^-4 + 9.5 x 10^-4
Basile [38]

Answer:

290

Step-by-step explanation:

I ask google it says 290

4 0
3 years ago
Plz help asap with a explanation of why that’s the answer
Olegator [25]

Answer:

1st option

Step-by-step explanation:

y = 1/2x + 2

7 0
3 years ago
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5<br> 1<br> The measure of Z1 =<br> O 55<br> O62.5<br> 110<br> 5
Akimi4 [234]

Answer: 55

Step-by-step explanation:

Congruent angles intercept congruent chords, so since the circumference of a circle is 360 degrees, the arc angle 1 is inscribed in measures 110 degrees.

So, by the inscribed angle theorem, angle 1 measures 55 degrees.

5 0
2 years ago
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