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3 years ago

15

How do I solve 2x+3=x+7

2 answers:

faltersainse [42]3 years ago

8 0

I hope I help you out

arsen [322]3 years ago

8 0

Answer:

X = 4

Step-by-step explanation:

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Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

2 years ago

A) 5<br> 11 + 4<br> 3<br> add the following rational number

mel-nik [20]

Step-by-step explanation:

the question is not correct

edit it and I will answer u in comments

5 0

2 years ago

18 is 4.5 times a number.

Bumek [7]

Answer:

4

Step-by-step explanation:

18/4.5=4

4 0

2 years ago

Read 2 more answers

Help again ;----; pls

yan [13]

Answer: Both 14, and 20

Step-by-step explanation:

8 0

2 years ago

Please help fast its quiz. :(

dezoksy [38]

Answer:

What is the question??

Thank you for the points

8 0

2 years ago

Read 2 more answers