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Lana71 [14]
3 years ago
6

When three squares are joined at their vertices to form a right triangle, the combined area of

Mathematics
1 answer:
zlopas [31]3 years ago
3 0

Answer:

..

Step-by-step explanation:

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Determine whether the graphs of any of the following equations are parallel or perpendicular. Explain
bixtya [17]

Answer:

y=4x and x+4y=12 are perpendicular because they have opposite reciprocal slopes

Step-by-step explanation:

y=4x slope is 4

x+4y=12 slope is -1/4

5 0
3 years ago
Factor the expression below. x2 - 4x + 4 A. 4(x2 - x + 1) B. (x - 2)(x + 2) C. (x + 2)(x + 2) D. (x - 2)(x - 2)
Tanzania [10]

Answer:

D. (x - 2)(x - 2)

Step-by-step explanation:

x2 - 4x + 4 = x² - 2x - 2x +4

                  = x(x-2)  -  2(x - 2)                    

                  = (x-2)(x-2)

HINT:   - 2x +4  = -2 * x  + (-2) * (-2) = -2 ( x -2)

4 0
3 years ago
Create a word problem that the equation 4x + 32 = 164 could represent.
Svetlanka [38]

It is a hot summer day, and Jade is trying to save money to buy a new shoe. She has 32 dollars, and she plans to sell smoothies at her neighborhood for four dollars a cup. At the end of the day, she is left with a total of 164 dollars in her wallet. How many smoothies did Jade sell?

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2 years ago
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Determine the annual insurance premium for 25/50 liability insurance for a driver having a rating factor of 1.85 if the base pre
marusya05 [52]
I would choose the answer B
8 0
3 years ago
Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants
lozanna [386]

Answer:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

Step-by-step explanation:

You have the following differential equation:

3y''+12y=0     (1)

In order to find the solution to the equation, you can use the method of the characteristic polynomial.

The characteristic polynomial of the given differential equation is:

3m^2+12=0\\\\m^2=-\frac{12}{3}=-4\\\\m_{1,2}=\pm2\sqrt{-1}=\pm2i

The solution of the differential equation is:

y(x)=c_1e^{m_1x}+c_2e^{m_2x}   (2)

where m1 and m2 are the roots of the characteristic polynomial.

You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

4 0
3 years ago
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