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almond37 [142]
3 years ago
10

2. How much heat is released when 432g of water cools down from 710C to 180C?

Chemistry
1 answer:
nadya68 [22]3 years ago
7 0
The heat released by the water when it cools down by a temperature difference AT

is Q = mC,AT

where

m=432 g is the mass of the water

C, = 4.18J/gºC

is the specific heat capacity of water

AT = 71°C -18°C = 530

is the decrease of temperature of the water

Plugging the numbers into the equation, we find

Q = (4329)(4.18J/9°C)(53°C) = 9.57. 104J

and this is the amount of heat released by the water.
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A geological sample is found to have a Pb-206/U-238 mass ratio of 0.337/1.00. Assuming there was no Pb-206 present when the samp
azamat

Answer:

Age=2.52*10^9 years

Explanation:

To determine the age, we need to know how much U have become Pb, so first we have to calculate the Pb moles present in a sample:

n_{Pb}=\frac{0.337g}{206g/mol}=0.00164 mol

n_{U}=\frac{1 g}{238g/mol}=0.0042 mol

The percentage of U degradation:

P=\frac{n_{Pb}}{n_{Pb}+n_{U}}

P=\frac{0.00164}{0.00164+0.0042}=0.28

Assuming that the life time is linear:

Age=\frac{4.5*10^9 years}{0.5 life time}*0.28 life time

Age=2.52*10^9 years

4 0
3 years ago
Read 2 more answers
Hydrogen has two naturally occurring isotopes, 1H and 2H. Chlorine also has two naturally occurring isotopes, 35Cl and 37Cl. Thu
rodikova [14]

Answer:

Molecules in order of decreasing rate of effusion:

^1{H}^{35}Cl>^2H^{35}Cl>^1H^{37}Cl>^2H^{37}Cl

Explanation:

Mass of ^1H^{35}Cl gas= M_1= 36 g/mol

Mass of ^1H^{37}Cl gas =M_2= 38 g/mol

Mass of ^2H^{35}Cl gas =M_3= 37 g/mol

Mass of ^2H^{37}Cl gas =M_4= 39 g/mol

According Graham's law:

'The rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas'.The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

So, higher the molecular mass of the gas lower will be the effusion rate and vice versa.

Increasing order of molecular masses of the given gases:

M_1

Decreasing order of effusion rate respective to gases:

R_1>R_3>R_2>R_4

Molecules in order of decreasing rate of effusion:

^{1}\textrm{H}^{35}Cl> ^{2}\textrm{H}^{35}Cl>^{1}\textrm {H}^{37}Cl>^{2}\textrm{H}^{37}Cl

8 0
3 years ago
Please show your work - thank you! :)
Evgen [1.6K]

Answer:

A. 4500 mL

Explanation:

We need to use a version of the combined gas law, which states:

\frac{V_1}{n_1T_1}= \frac{V_2}{n_2T_2} , where T represents temperature, V volume, and n moles

First, look at the initial values of n, V, and T:

- n: we have 10.0 grams of hydrogen, which we need to convert to moles. So: 10.0g*\frac{1 mol}{2.02 g} =4.95molH_2

- V: we have a volume of 5.0 L

- T: our temperature right now is 28.0°C, but we need it in Kelvins, so add 273: 28.0 + 273 = 301 K

Now look at the final values:

- n: our final number of grams is 8.5 grams of hydrogen, so we need to convert this to moles.

8.5g*\frac{1 mol}{2.02 g} =4.2molH_2

- V: this is what we want to find

- T: our final temperature is 44.0°C; to convert it to Kelvins, add 273.

44.0 + 273 = 317 K

Put this altogether:

\frac{V_1}{n_1T_1}= \frac{V_2}{n_2T_2}

\frac{5.0}{4.95*301}= \frac{V_2}{4.2*317}

Multiply both sides by (4.2 * 317):

V_2 ≈ 4.5 L

However, the problem wants millilitres, so simply multiply 4.5 by 1000:

4.5 * 1000 = 4500

The answer is thus A.

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3 years ago
Changing colors is not an indication of a chemical change.<br> a. True<br> b. False
Nata [24]
Idk but ithink is F
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3 years ago
What is a bond between positive and negative ion called?
amm1812

It is called a ionic bond or a electrovalent bond. Hope it helps :)

8 0
3 years ago
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