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Anettt [7]
3 years ago
5

The line passes through (9,8) and is perpendicular to x-2y=-16

Mathematics
1 answer:
pickupchik [31]3 years ago
4 0

The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26

Step-by-step explanation:

Given

x-2y=-16\\Adding\ 2y\ on\ both\ sides\\x=2y-16\\Adding\ 16\ on\ both\ sides\\x+16=2y-16+16\\x+16=2y\\2y=x+16\\Dividing\ both\ sides\ by\ 2\\\frac{2y}{2}=\frac{x+16}{2}\\y=\frac{x}{2}+\frac{16}{2}\\y=\frac{1}{2}x+8\\

The equation is in slope-intercept form,  the coefficient of x will be the slope of given line. The slope is: 1/2

As the product of slopes of two perpendicular lines is -1.

\frac{1}{2}*m=-1\\m=-1*\frac{2}{1}\\m=-2

Slope intercept form is:

y=mx+b

Putting the value of slope

y=-2x+b

To find the value of b, putting (9,8) in the equation

8=-2(9)+b\\8=-18+b\\b=8+18\\b=26

Putting the values of b and m

y=-2x+26

Hence,

The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26

Keywords: Equation of line, Slope-intercept form

Learn more about equation of line at:

  • brainly.com/question/1993757
  • brainly.com/question/2048256

#LearnwithBrainly

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