The line passes through (9,8) and is perpendicular to x-2y=-16

Mathematics

1 answer:

pickupchik [31]3 years ago

4 0

The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26

Step-by-step explanation:

Given

$x-2y=-16\\Adding\ 2y\ on\ both\ sides\\x=2y-16\\Adding\ 16\ on\ both\ sides\\x+16=2y-16+16\\x+16=2y\\2y=x+16\\Dividing\ both\ sides\ by\ 2\\\frac{2y}{2}=\frac{x+16}{2}\\y=\frac{x}{2}+\frac{16}{2}\\y=\frac{1}{2}x+8\\$

The equation is in slope-intercept form, the coefficient of x will be the slope of given line. The slope is: 1/2

As the product of slopes of two perpendicular lines is -1.

$\frac{1}{2}*m=-1\\m=-1*\frac{2}{1}\\m=-2$

Slope intercept form is:

$y=mx+b$

Putting the value of slope

y=-2x+b

To find the value of b, putting (9,8) in the equation

$8=-2(9)+b\\8=-18+b\\b=8+18\\b=26$

Putting the values of b and m

$y=-2x+26$

Hence,

The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26

Keywords: Equation of line, Slope-intercept form

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67. The line contains the point (4,0) and is parallel to the line defined by 3x = 2y.

olganol [36]

Answer:

$y=\frac{3}{2} x-6$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form:

$y=mx+b$ where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)

Parallel lines will always have the same slope but different y-intercepts.

1) Determine the slope of the parallel line

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

$3x = 2y$

Switch the sides

$2y=3x$

Divide both sides by 2 to isolate y

$\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x$

Now that this equation is in slope-intercept form, we can easily identify that $\frac{3}{2}$ is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope $\frac{3}{2}$ . Plug this into $y=mx+b$ :