Answer:
1813.137 KJ
Step-by-step explanation:
potential energy of the body = mgH
where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m
here m= 1000 kg, g= 9.81 m/s^2 and H= 607 feet = 607×0.305= 185.135 m
hence the potential energy p= 1000×9.81×185.135= 1813137.2 J
= 1813.137 KJ
hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ
Answer:
Set up your height equation, then factor or use quadratic formula to find when h(t)=0
Step-by-step explanation:
Your equation will be -16t^2+vt +h where v is the initial velocity and h is the starting height. Now either factor or quadratic equation, whichever is easier for you.
Remember that the ball is on the ground when h(t)=0 since that is the height. There will be two zeros, one is a negative number so would be before you kicked the ball, the other one will be when the ball comes back down.
The measurement of angle b is 128°
AC is a common side, ∠ACD = ∠ACB and CD = BC ⇒ ΔACD and ΔABC <span>are congruent (SAS definition).
</span>Congruent triangles have exactly the same three angles, so ∠D = ∠B.<span>
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