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3 years ago

rachel jogged along a trail that was 1/4 of a mile long. She jogged along the trail 8 times. how many miles did rachel jog?

1 answer:

4 0

To solve for how many miles Rachel jogged if she jogged a 1/4 mile trail 8 times, we simply need to multiply the distance she ran each time by the amount of times she ran it.

1/4 * 8 = 2

Rachel jogged 2 miles.
Hope that helped =)

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What is 1/3 of 3/2 of 4/5?

viktelen [127]

1/3 of 3/2 of 4/5 would be 0.4

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2 years ago

Use a graph in a (-2π, 2π, π/2) by (-3, 3, 1) viewing rectangle to complete the identity.

yaroslaw [1]

First, notice that:

$2\tan (\frac{x}{2})=2\cdot(\pm\sqrt[]{\frac{1-cosx}{1+\cos x})}$

And in the denominator we have:

$1+\tan ^2(\frac{x}{2})=1+\frac{1-\cos x}{1+\cos x}=\frac{1+cosx+1-\cos x}{1+cosx}=\frac{2}{1+\cos x}$

then, we have on the original expression:

$\begin{gathered} \frac{2\tan(\frac{x}{2})}{1+\tan^2(\frac{x}{2})}=\frac{2\cdot\pm\sqrt[]{\frac{1-\cos x}{1+cosx}}}{\frac{2}{1+\cos x}}=\frac{2\cdot(\pm\sqrt[]{1-cosx})\cdot(1+\cos x)}{2\cdot(\sqrt[]{1+cosx})} \\ =(\sqrt[]{1-\cos x})\cdot(\sqrt[]{1+\cos x})=\sqrt[]{(1-\cos x)(1+\cos x)} \\ =\sqrt[]{1-\cos^2x}=\sqrt[]{\sin^2x}=\sin x \end{gathered}$

therefore, the identity equals to sinx

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1 year ago

Celia ate 5/8 of a pizza what decimal is equivalent to the fraction of pizza celia ate

Naddik [55]

Answer:

0.625

Step-by-step explanation:

5÷8=0.625

This is equal to the number of pizzas Celia ate.

plz mark me as brainliest.

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2 years ago

Read 2 more answers

Simplify (2/5÷3/8)÷(-3/5)

liberstina [14]

Answer:

$\pink{ - 1 \frac{7}{9} }$

Step-by-step explanation:

$( \frac{2}{5} \div \frac{3}{8} ) \div ( - \frac{3}{5} ) \\ (\frac{2}{5} \times \frac{8}{3} ) \times ( - \frac{5}{3} ) \\ \frac{16}{15} \times - \frac{5}{3} \\ - \frac{80}{45}$

As the answer can be more simplified, divide both numerator and denominator by 5.

$- \frac{16}{9} = - 1 \frac{7}{9}$

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1 year ago

Evaluate <br> 4x3x8-2x(8x5-37)

Zigmanuir [339]

Answer:

$4x^1^1-16x^6+74x$

Step-by-step explanation:

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2 years ago