See the attached figure.
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AB = 10 , FD = 3
∵ D is the midpoint of AB, and F is the mid point of CB
∴ FD // AC , FD = 0.5 AC
∵ Δ ABC is a right triangle at C
∴ FD ⊥ BC
∴ BD = 0.5 AB = 5
∴ in Δ FDB ⇒⇒ BF² = BD² - FD² = 5² - 3² = 16
∴ BF = √16 = 4
∵ F is the mid point of CB
∴ CF = BF = 4 , and CB = 2 BF = 2*4 = 8
∵ D is the midpoint of AB, and E is the mid point of AC
∴ DE // CB , and DE = 0.5 CB = 0.5 * 8 = 4
∴ T<span>he length of line ED is 4
</span>
Answer: 110°
<u>Step-by-step explanation:</u>
∠A ≅ ∠B
since ∠A = 35° (given), then ∠B = 35°
Use the Triangle Sum Theorem to find ∠C:
∠A + ∠B + ∠Q = 180°
35° + 35° + ∠Q = 180°
70° + ∠Q = 180°
∠Q = 110°
The central angle (∠AQB) ≅ arc AB
since ∠AQB = 110° (solved above), then arc AB = 110°
We are given the vertices of the triangle with their respective coordinates. For the vertex L, the translated coordinates is also given. So, from the original coordinates of L and the new coordinates, we can get the rule used during translation:(7, -3) -> (7 + a, -3 + b) = (-1, 8)7 + a = -1a = -8
-3 + b = 8b = 11
Therefore, the answer is:(x, y) → (x – 8, y + 11)
If 24 of the 60 were saved then the percent saved is
(24/60) x 100
Let's imagine for a second that all 60 was saved, then 100% of the money would be saved. Which makes sense, because
(60/60) x 100 = 100%
So the amount saved dived by the amount earned all times 100 is the percent saved.
Hi there!
From this problem we can pull out some key information and remove any excess.
- The trail is 1/4 of a mile long.
- Angelo rode around the trail 8 times.
- Angelo claims he rode 8/4 miles.
- Teresa claims he rode 2 miles.
From that we know that if Angelo rode around the trail 8 times and the trail is 1/4 a mile, he in total rode 8/4 of a mile.
However, Teresa claims he rode 2 miles!
And the answer is... they're both correct!
Angelo did indeed ride 8/4 miles however that is equivalent to 2 miles so they are both in the right.
