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SCORPION-xisa [38]
3 years ago
9

to make a shade of plant called Jasper Green, Mix 4 quarts of green paint with 2/3 cups of black paint. how much green paint sho

uld be mixed with 4 cups of black paint to make Jasper Green?
Mathematics
2 answers:
Alinara [238K]3 years ago
7 0
96 cups of green for
4 cups of black
r-ruslan [8.4K]3 years ago
4 0

Answer

24 quarts of green paint should be mixed with 4 cups of black paint.

That is (96 cups)

Step by step explanation

Jasper Green mix 4 quarts of green paint with 2/3 cups of black paint.

Let's convert 4 quarts into cups.

1 quart = 4 cups

4 quarts = 16 cups

Here mix 16 cups of green paint with 2/3 cups of black paint.

Let's use the proportion

Green paint                      Black paint

16                                          2/3

x                                            4

16/x =2/3 divided by 4

\frac{16}{x}  = \frac{2/3}{4}

Cross multiplying, we get

16*4 = 2/3 x

64 = 2/3 x

x = 64/(2/3)

x = 64 * 3/2

x = 192/2

x = 96 cups

96 cups of green paint should be mixed with 4 cups of black paint.

We can covert 96 cups into quarts by dividing by 4

96/4 = 24 quarts

24 quarts of green paint should be mixed with 4 cups of black paint.

Thank you.

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Please help!! What Find the Error and explain why it is wrong!
Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. The real numerator in Step E should be:

3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x

Hence, Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

And further steps are described below:

Step D

x^{2}-x+4 = 0

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: (a = 1, b = -1, c = 4)

D = b^{2}-4\cdot a\cdot c

D = (-1)-4\cdot (1)\cdot (4)

D = -17 (Conjugated complex roots)

Step E

(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0

Step F

x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936

8 0
3 years ago
A provider order has been received for a dobutamine (dobutrex®) drip at 7 mcg/kg/min. the patient's weight is 220 lbs. how many
Liula [17]
To figure this out you first need to determine how many kg there are in 220 lbs. 1 lb equals 0.454 kg, so 220 lbs= 99.88 kg.

It states that a patient receives 7mcg per kg per minute, so the patient will receive 7 x 99.88=699.16 mcg per minute.

You need to convert this to a number of mcg per hour, so multiply the amount by 60 to get 41949.6 mcg per hour.
4 0
2 years ago
20 points! Will mark the brainliest!
andrew-mc [135]
\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

-----------------------------------------------------------------------------------
Write the divide fraction horizontally:
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= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

-----------------------------------------------------------------------------------
Factorise the numerators and denominators when possible:
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= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

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Convert the divide fraction to multiplication fraction
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= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

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Cancel the factors
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= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

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Combine to single fraction
-----------------------------------------------------------------------------------

= \dfrac{1}{4(x+2)^2}



4 0
3 years ago
Sten sat on a bench and read a book while Manu was at soccer practice. He read for 35 minutes and stopped at 6:10 p.m.
Dahasolnce [82]

Answer:

5:35

Step-by-step explanation:

6 0
3 years ago
the circle below has center T. suppose that m UV = 138 degrees and that UW is tangent to the circle at U. find the following
alisha [4.7K]

Angle UTV is basically given: it's 138°.

Moreover, since UTV is isosceles, the other two angles have the same measure x. We thus have

138+x+x=180 \iff 2x=42 \iff x=21

So, TUV is 21°, and VUW is complementary, so it must be 69° so that they sum up to 90°

3 0
3 years ago
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