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Anna [14]
3 years ago
11

This container is composed of a right circular cylinder and a right circular cone. The diameter is 20, the height of the cylinde

r is 9, and the slant height of the cone is 16. Find the surface area
Mathematics
1 answer:
kupik [55]3 years ago
3 0

Answer:

<h2> Total -CSA= 1068.28</h2>

Step-by-step explanation:

This problem is on the mensuration of solids, a cylinder and a cone combined (a frustum)

We are required to solve for the total curve surface areas both solids

hence the curve surface area (henceforth CSA) of a cylinder is given as

CSA-cylinder=2\pi rh

CSA-cone= \pi rl

Total CSA= 2\pi rh+\pi rl

Given data

diameter d= 20

radius = d/2= 20/2= 10

height of cylinder h= 9

slant height of cone l= 16

substituting our data into the expression we have

Total -CSA= 2*\pi *10*9+\pi *10*16\\\\Total -CSA= 565.56+502.72\\\Total -CSA= 1068.28

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Using the angle sum identities for sine and cosine,

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

yields

tan(A + B) = (sin(A) cos(B) + cos(A) sin(B)) / (cos(A) cos(B) - sin(A) sin(B))

Multiplying the right side by 1/(cos(A) cos(B)) uniformly gives

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A) tan(B))

Since 2 tan(A) = 3 tan(B), it follows that

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Putting everything back in terms of sin and cos gives

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Multiplying uniformly by cos²(B) gives

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Recall the double angle identities for sin and cos:

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