This container is composed of a right circular cylinder and a right circular cone. The diameter is 20, the height of the cylinde
1 answer:
Answer:
<h2> Total -CSA= 1068.28</h2>Step-by-step explanation:
This problem is on the mensuration of solids, a cylinder and a cone combined (a frustum)
We are required to solve for the total curve surface areas both solids
hence the curve surface area (henceforth CSA) of a cylinder is given as
Given data
diameter d= 20
radius = d/2= 20/2= 10
height of cylinder h= 9
slant height of cone l= 16
substituting our data into the expression we have
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1) 4.55
2) Short hit
Step-by-step explanation:
1)
The table containing the score and the relative probability of each score is:
Score 3 4 5 6 7
Probability 0.15 0.40 0.25 0.15 0.05
Here we call
X = Miguel's score on the Water Hole
The expected value of a certain variable X is given by:
where
are all the possible values that the variable X can take
is the probability that
Therefore in this problem, the expected value of MIguel's score is given by:
2)
In this problem, we call:
X = Miguel's score on the Water Hole
Here we have that:
- If the long hit is successfull, the expected value of X is
- Instead, if the long hit fails, the expected value of X is
Here we also know that the probability of a successfull long hit is
Which means that the probabilty of an unsuccessfull long hit is
Therefore, the expected value of X if Miguel chooses the long hit approach is:
In part 1) of the problem, we saw that the expected value for the short hit was instead
Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.