1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr402 [8]
3 years ago
12

Nathan has a sculpture in the shape of a pyramid. The height of the sculpture is 3 centimeters less than the side length,x,of it

s square base. Nathan uses the formula for the volume of a pyramid to determine the dimesnsioms of the sculpture.
V=1/3 a^2h
Here, a is the side length of the pyramids square base and h is it’s height.

If 162 cubic centimeters of clay were used to make the sculpture, the equation x^3+_x^2+_=0 can be used to find that the length of the sculptures base is _ centimeters.
Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0

Answer:

side length of sculpture = 9 cm

height of sculpture = 6cm

Step-by-step explanation:

Given that,

volume of sculpture = 162cm³

side length of sculpture = x

height of sculpture = x-3

formula for volume of sculpture

<h3>V=1/3 a²h</h3>

by putting values, the equation can be used to find the length of the sculpture’s base

162 = 1/3 (x)² (x-3)

162(3) =  (x)² (x-3)

486 = x²(x-3)

486 = x³ - 3x²

x³ - 3x² - 486 = 0

x = 9 <em>(using a graph tool / calculator equation mode)</em>

side length of sculpture = 9 cm

height of sculpture = 9 - 3

                                 = 6cm

You might be interested in
Stephanie had 22 marbles. she gave maggie and sam each 4 marbles. explain how you can find how many marbles stephanie has left?
Lina20 [59]
She had 22 marbles and gave away, 4 to two people, so 4*2 = 8. 22-8=14. she has 14 marbles left.
4 0
3 years ago
Solve this inequality: 8z + 3 – 2z &lt; 51
MArishka [77]
8z +3 - 2z < 51
6z + 3 < 51
-3. -3
6z < 48
-- ---
6. 6

z<8
8 0
3 years ago
Read 2 more answers
The length of the rectangle is three more than the width find the length of the rectangle if the perimeter is 98 inches
Aleks [24]

Answer:

length is 26 and width is 23

Step-by-step explanation:

let width be x

then length is 3+x since it is 3 more than the width

perimeter of a rectangle = 2l + 2w

98=2 [3+x] + 2x

98=6+2x+2x

98=6+4x

98-6=4x

92=4x

x=23

width is 23 and

breadth is 26

5 0
3 years ago
If I got 32 hits out of 112 at bats what is my batting average?
ddd [48]
29% all you have to do is divide
32/112
3 0
3 years ago
Find a solution of x dy dx = y2 − y that passes through the indicated points. (a) (0, 1) y = (b) (0, 0) y = (c) 1 6 , 1 6 y = (d
Leni [432]
Answers: 

(a) y = \frac{1}{1 - Cx}, for any constant C

(b) Solution does not exist

(c) y = \frac{256}{256 - 15x}

(d) y = \frac{64}{64 - 15x}

Explanations:

(a) To solve the differential equation in the problem, we need to manipulate the equation such that the expression that involves y is on the left side of the equation and the expression that involves x is on the right side equation.

Note that

 x\frac{dy}{dx} = y^2 - y&#10;\\&#10;\\ \indent xdy = \left ( y^2 - y \right )dx&#10;\\&#10;\\ \indent \frac{dy}{y^2 - y} = \frac{dx}{x}&#10;\\&#10;\\ \indent \int {\frac{dy}{y^2 - y}} = \int {\frac{dx}{x}} &#10;\\&#10;\\ \indent \boxed{\int {\frac{dy}{y^2 - y}} = \ln x + C_1}      (1)

Now, we need to evaluate the indefinite integral on the left side of equation (1). Note that the denominator y² - y = y(y - 1). So, the denominator can be written as product of two polynomials. In this case, we can solve the indefinite integral using partial fractions.

Using partial fractions:

\frac{1}{y^2 - y} = \frac{1}{y(y - 1)} = \frac{A}{y - 1} + \frac{B}{y}&#10;\\&#10;\\ \indent \Rightarrow \frac{1}{y^2 - y} = \frac{Ay + B(y-1)}{y(y - 1)} &#10;\\&#10;\\ \indent \Rightarrow \boxed{\frac{1}{y^2 - y} = \frac{(A+B)y - B}{y^2 - y} }      (2)

Since equation (2) has the same denominator, the numerator has to be equal. So,

1 = (A+B)y - B&#10;\\&#10;\\ \indent \Rightarrow (A+B)y - B = 0y + 1&#10;\\&#10;\\ \indent \Rightarrow \begin{cases}&#10; A + B = 0&#10;& \text{(3)}\\-B = 1&#10; & \text{(4)}   \end{cases}

Based on equation (4), B = -1. By replacing this value to equation (3), we have

A + B = 0
A + (-1) = 0
A + (-1) + 1 = 0 + 1
A = 1 

Hence, 

\frac{1}{y^2 - y} = \frac{1}{y - 1} - \frac{1}{y}

So,

\int {\frac{dy}{y^2 - y}} = \int {\frac{dy}{y - 1}} - \int {\frac{dy}{y}} &#10;\\&#10;\\ \indent \indent \indent \indent = \ln (y-1) - \ln y&#10;\\&#10;\\ \indent  \boxed{\int {\frac{dy}{y^2 - y}} = \ln \left ( \frac{y-1}{y} \right ) + C_2}

Now, equation (1) becomes

\ln \left ( \frac{y-1}{y} \right ) + C_2 = \ln x + C_1&#10;\\&#10;\\ \indent \ln \left ( \frac{y-1}{y} \right ) = \ln x + C_1 - C_2&#10;\\&#10;\\ \indent  \frac{y-1}{y} = e^{C_1 - C_2}x&#10;\\&#10;\\ \indent  \frac{y-1}{y} = Cx, \text{ where } C = e^{C_1 - C_2}&#10;\\&#10;\\ \indent  1 - \frac{1}{y} = Cx&#10;\\&#10;\\ \indent \frac{1}{y} = 1 - Cx&#10;\\&#10;\\ \indent \boxed{y = \frac{1}{1 - Cx}}&#10;       (5)

At point (0, 1), x = 0, y = 1. Replacing these values in (5), we have

y = \frac{1}{1 - Cx}&#10;\\&#10;\\ \indent 1 = \frac{1}{1 - C(0)} = \frac{1}{1 - 0} = 1&#10;&#10;

Hence, for any constant C, the following solution will pass thru (0, 1):

\boxed{y = \frac{1}{1 - Cx}}

(b) Using equation (5) in problem (a),

y = \frac{1}{1 - Cx}   (6)

for any constant C.

Note that equation (6) is called the general solution. So, we just replace values of x and y in the equation and solve for constant C.

At point (0,0), x = 0, y =0. Then, we replace these values in equation (6) so that 

y = \frac{1}{1 - Cx}&#10;\\&#10;\\ \indent 0 = \frac{1}{1 - C(0)} = \frac{1}{1 - 0} = 1

Note that 0 = 1 is false. Hence, for any constant C, the solution that passes thru (0,0) does not exist.

(c) We use equation (6) in problem (b) and because equation (6) is the general solution, we just need to plug in the value of x and y to the equation and solve for constant C. 

At point (16, 16), x = 16, y = 16 and by replacing these values to the general solution, we have

y = \frac{1}{1 - Cx}&#10;\\&#10;\\ \indent 16 = \frac{1}{1 - C(16)} &#10;\\ &#10;\\ \indent 16 = \frac{1}{1 - 16C}&#10;\\&#10;\\ \indent 16(1 - 16C) = 1&#10;\\ \indent 16 - 256C = 1&#10;\\ \indent - 256C = -15&#10;\\ \indent \boxed{C = \frac{15}{256}}&#10;&#10;&#10;

By replacing this value of C, the general solution becomes

y = \frac{1}{1 - Cx}&#10;\\&#10;\\ \indent y = \frac{1}{1 - \frac{15}{256}x} &#10;\\ &#10;\\ \indent y = \frac{1}{\frac{256 - 15x}{256}}&#10;\\&#10;\\&#10;\\ \indent \boxed{y = \frac{256}{256 - 15x}}&#10;&#10;&#10;&#10;

This solution passes thru (16,16).

(d) We do the following steps that we did in problem (c):
        - Substitute the values of x and y to the general solution.
        - Solve for constant C

At point (4, 16), x = 4, y = 16. First, we replace x and y using these values so that 

y = \frac{1}{1 - Cx} &#10;\\ &#10;\\ \indent 16 = \frac{1}{1 - C(4)} &#10;\\ &#10;\\ \indent 16 = \frac{1}{1 - 4C} &#10;\\ &#10;\\ \indent 16(1 - 4C) = 1 &#10;\\ \indent 16 - 64C = 1 &#10;\\ \indent - 64C = -15 &#10;\\ \indent \boxed{C = \frac{15}{64}}

Now, we replace C using the derived value in the general solution. Then,

y = \frac{1}{1 - Cx} \\ \\ \indent y = \frac{1}{1 - \frac{15}{64}x} \\ \\ \indent y = \frac{1}{\frac{64 - 15x}{64}} \\ \\ \\ \indent \boxed{y = \frac{64}{64 - 15x}}
5 0
3 years ago
Other questions:
  • A tornado traveled 260 miles in 4 hours. If the average rate at which the tornado is moving slows by 20%, how many miles will th
    7·2 answers
  • Estimate the value 13 to the nearest 0.05
    10·1 answer
  • Whic transformation can verify congruence by sliding one triangle over another
    14·2 answers
  • Kenneth bought a new roll of tape. There were 59.6 yards of tape on the roll. Then Kenneth used 4 yards of the tape to make a co
    9·2 answers
  • Brandy is making a peach pie for her grandmother for christmas. the diameter of the pie is 12 in. if three-fourths of the area o
    11·1 answer
  • -3 - 8+ (-4) what is the answer??
    9·2 answers
  • Why do you multiply the tax and the money 3.38 aren’t you supposed to add
    15·1 answer
  • Is x(4x^2+8x+12) completely factored? If not how else can it be factored ?
    10·1 answer
  • Estimate 4,137 (please quick!)
    15·1 answer
  • Matthew's family traveled 3/8 of the distance to his grandmother’s house on Saturday. They traveled 3/5 of the remaining distanc
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!