Question

A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it reaches?
PLEASE HELP ASAP, A LOT OF POINTS PROVIDED

Answer 1

Answer: 61.25m

Step-by-step explanation:

To solve this, the formula used will be:

h = -16t^2 + vt + h(o)

where,

Initial velocity, v = 60mph

Height, h = 5 feet

t = ?

After solving for t, we get t = 1.875 seconds. We then slot it back into the equation.

h = -16t^2 + vt + h(o)

h = -16(1.875)^2 + 60(1.875) + 5

h = -56.25 + 1112.5 + 5

h = 61.25m

Check the attachment for better understanding.