Answer:
step-by-step explanation:
You have to solve this to get your answer. This is a case where you have to use the pythagorean theorem.
A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it
reaches?
PLEASE HELP ASAP, A LOT OF POINTS PROVIDED
PLEASE HELP ASAP, A LOT OF POINTS PROVIDED
1 answer:
Answer: 61.25m
Step-by-step explanation:
To solve this, the formula used will be:
h = -16t^2 + vt + h(o)
where,
Initial velocity, v = 60mph
Height, h = 5 feet
t = ?
After solving for t, we get t = 1.875 seconds. We then slot it back into the equation.
h = -16t^2 + vt + h(o)
h = -16(1.875)^2 + 60(1.875) + 5
h = -56.25 + 1112.5 + 5
h = 61.25m
Check the attachment for better understanding.
You might be interested in
Answer:
= 2
= k(k+1)
= (k+1)(k+2)
Step-by-step explanation:
We are given the statement,
as 2 + 4 + 6 + . . . + 2n = n(n+1)
That is,
as 2 + 4 + 6 + . . . + 2n =
So, we have,
=
= 2
=
= 2 + 4 + 6 + . . . + 2k = k(k+1)
=
= 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)
Thus, we get,
= 2
= k(k+1)
= (k+1)(k+2)
Good luck.............................
