The given parallelogram is a rhombus
Solution:
Option A: Rhombus
Let us recall the property of rhombus.
- Diagonals bisect each other at right angles.
- Opposite angles are congruent.
Here diagonals bisect the angles equally each 72°.
Opposite angles are congruent(72° + 72° = 144°).
Hence the given parallelogram is a rhombus.
Option B: Rectangle
Let us recall the property of rectangle.
- Diagonals bisect each other.
- All the angles of a rectangle are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a rectangle.
Option C: Square
Let us recall the property of square.
- Diagonals bisect each other.
- All the angles of a square are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a square.
Answer:
94666.093488
Step-by-step explanation:
you could have used a calculator for a faster answer but I guess this is fine too
-8x+7-6(x-1)=-6x-(7x-5)+6
-8x+7-6x+6=-6x-7x+5+6
use gemdas to add like terms
-14x+13=-13x+11
+14x. +14x
13= x+11
-11 -11
2=x
Can you add a little bit more detail? Am I finding out how much the difference is or something?
Answer:
A) 15/52
Step-by-step explanation:
Good luck with your assignment
