Answer:
The perimeter of triangle is 19.8 units
Step-by-step explanation:
we know that
The perimeter of triangle ABC is

the formula to calculate the distance between two points is equal to

step 1
Find the distance AB
we have

substitute in the formula



step 2
Find the distance BC
we have

substitute in the formula



step 3
Find the distance AC
we have

substitute in the formula



step 4
Find the perimeter

substitute the values


You didnt give enough information but 40
<span>Answer:
Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home.
:
Let s = original speed
then
(s+11) = return speed
:
Write a time equation: Time = distance%2Fspeed
:
Original time = return time + 1 hr
330%2Fs = 330%2F%28%28s%2B11%29%29 + 1
:
Multiply equation by s(s+11) and you have:
330(s+11) = 330s + s(s+11)
:
330s + 3630 = 330s + s^2 + 11s
:
0 = 330s - 330s + s^2 + 11s - 3630
:
A quadratic equation:
s^2 + 11s - 3630 = 0
Factor this to:
(s + 66)(s - 55) = 0
Positive solution
s = 55 mph is original speed.
:
Find the time
330/55 = 6 hr, original time
and
330/66 = 5 hrs, faster time; confirms our solution.</span>
Answer:
What is the question I understand the part where you need a ratio as a fraction but, is there a way you can put a pic of the numbers or put the numbers in the question?
Answer:
parallel
Step-by-step explanation:
find the slope of each line
Line 1 (5-2)/(-4-2) = 3/-6 =-1/2
Line 2 (-4--9)/(-6-4)= 5/-10 = -1/2