Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
Answer:
f'(1x) = 2x
or
f'(0) = 4
Step-by-step explanation:
Hope this helps if not im sorry
Answer:
B. x^2
Step-by-step explanation:
Answer:
3/4 lb
Step-by-step explanation:
You can use multiplication:
3 × 1/4 lb = 3/1 × 1/4 lb = 3/4 lb
You can also use addition:
1/4 lb + 1/4 lb + 1/4 lb = 3/4 lb
Answer:the second one is the answer
Step-by-step explanation:I did this last year
