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jolli1 [7]
2 years ago
7

Matthew had to make a bridge for his math class. It had to be at least 1 1/2 feet long. Harold made a bridge that was 2 1/3 time

s as long as Matthew’s. What equation would you use to find out how long Harold’s bridge is?
Mathematics
1 answer:
Fed [463]2 years ago
7 0

The equation used for finding the length of Harold's bridge will be 3H-7M=0 Length will be H = 1/√2

<h3>What is an equation?</h3>

The equation in mathematics is the relationship between the variables and the number and establishes the relationship between the two or more variables.

Here we have the following data:-

Matthew's bridge length is

 1(1/2)=3/2

Now we have that Harold made a bridge that was 2 1/3 times as long as Matthew’s. From this data the equation will be:-

H=2\dfrac{1}{3}M\\\\\\H-\dfrac{7}{3}M=0\\\\\\3H-\dfrac{7\times 3}{2}=0\\\\\\H=\dfrac{1}{\sqrt{2}}

The equation used for finding the length of Harold's bridge will be 3G-7M=0 Length will be H = 1/√2

To know more about equations follow

brainly.com/question/2972832

#SPJ1

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Answer:


Step-by-step explanation:

xy = k    

where k is the constant of variation.

We can also express the relationship between x and y as:

y =      

where k is the constant of variation.

Since k is constant, we can find k given any point by multiplying the x-coordinate by the y-coordinate. For example, if y varies inversely as x, and x = 5 when y = 2, then the constant of variation is k = xy = 5(2) = 10. Thus, the equation describing this inverse variation is xy = 10 or y = .

Example 1: If y varies inversely as x, and y = 6 when x = , write an equation describing this inverse variation.

k = (6) = 8  

xy = 8 or y =  

Example 2: If y varies inversely as x, and the constant of variation is k = , what is y when x = 10?

xy =  

10y =  

y = × = × =  

k is constant. Thus, given any two points (x1, y1) and (x2, y2) which satisfy the inverse variation, x1y1 = k and x2y2 = k. Consequently, x1y1 = x2y2 for any two points that satisfy the inverse variation.

Example 3: If y varies inversely as x, and y = 10 when x = 6, then what is y when x = 15?

x1y1 = x2y2  

6(10) = 15y  

60 = 15y  

y = 4  

Thus, when x = 6, y = 4.



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