Question

Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths

Answer 1

The value of the cosine ratio cos(L) is 5/13

How to determine the cosine ratio?

The complete question is added as an attachment

Start by calculating the hypotenuse (h) using

h^2 = 5^2 + 12^2

Evaluate the exponent

h^2 = 25 + 144

Evaluate the sum

h^2 = 169

Evaluate the exponent of both sides

h = 13

The cosine ratio is then calculated as:

cos(L) = KL/h

This gives

cos(L) =5/13

Hence, the value of the cosine ratio cos(L) is 5/13

Read more about right triangles at:

brainly.com/question/2437195

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