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Vsevolod [243]
3 years ago
15

(I will give brainliest. Please answer quickly)

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

The first step to solve this problem is to find the area of the rectangular piece of fabric.

A of triangle = bh/2

A = (14 cm) (6 cm) /2

A = 84 cm^2 / 2

A = 42 cm

And since there are 31 pieces of the fabric, the total area of all the pieces of fabric is:

31 pieces of fabric x 42 square centimeters per piece = 1,302 square centimeters

To computer how many congruent triangular patches can be cut, you have to divide the total area of the fabric pieces with the area of the congruent triangle:

1,302 square centimeters / 21 square centimeters = 62

Therefore, Leia can cut 62 patches.

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What is the slope of the line from the table below hour: 1, 2, 4, 8 distance: 50, 100, 200, 400
VLD [36.1K]

Answer:

50

Step-by-step explanation:

The slope is change in y divided by the change in x

Change in distance / change in hour

m = (400-200)/(8-4)

   = 200/4

  = 50

4 0
3 years ago
P(x)= 3x^3-5x^2-14x-4
nexus9112 [7]
   
\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\


\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)


\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



7 0
3 years ago
Please help me<br> Solve for x.<br> a) 30<br> b) 27<br> c) 33
OlgaM077 [116]

Answer:

x = 27

Step-by-step explanation:

The angle at any point on a straight line is 180 degrees.

The middle line over there is creating a right angle which is 90 degrees.

This must mean that both sides are 90 degrees.

3x+9 = 90

3x = 81

x = 27

4 0
3 years ago
Question: A box of chocolates contains square chocolates, which weigh 10 g each, and round chocolates, which weigh 8 g each. The
Viktor [21]

Answer: the box contained 9 square chocolates and 15 round chocolates.

Step-by-step explanation:

Let x represent the number of square chocolates contained in the box.

Let y represent the number of round chocolates contained in the box.

The box of chocolates contains square chocolates, which weigh 10g each and round chocolates which weigh 8g each. The combined weight of all the chocolates is 210g. It means that

10x + 8y = 210- - - - - - - - - - -1

The number of round chocolates is 3 less than twice the number of square chocolates. It means that

y = 2x - 3

Substituting y = 2x - 3 into equation 1, it becomes

10x + 8(2x - 3) = 210

10x + 16x - 24 = 210

26x = 210 + 24

26x = 234

x = 234/26

x = 9

y = 2x - 3 = 2 × 9 - 3

y = 18 - 3

y = 15

3 0
3 years ago
Silvio is an air-traffic controller who must calculate the altitude of an incoming plane. He sees the plane at an angle of eleva
Mrac [35]
Since the problem is not telling us the height of Silvio, we are going to assume it is not relevant for our calculations.
Let h the altitude of the incoming plane. We know for our problem that the distance between Silvio and the tower is 3 miles, Also we know that the angle of elevation to the plane is 40°. With this information we can create a triangle as shown in the figure. We need a function that relates the angle of elevation with its opposite and adjacent sides, that function is tangent.
tan \alpha = \frac{opposite.side}{adjacent.side}
tan(40)= \frac{h}{3}
h=3tan(40)
h=2.5miles

We can conclude that we should use the trig function tangent to model this situation; also, we can conclude that the equation that describes this situation is h=3tan(40).

4 0
3 years ago
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