We know that
the equation of a vertical parabola in vertex form
y=a*(x-h)²+k
(h,k)------> (0,5)
y=a*(x-0)²+5
y=a*x²+5
substitute the point (2,9) in the equation
9=a*(2)²+5------> 9=4*a+5-------> 4*a=9-5-----> 4*a=4-----> a=1
the equation of the vertical parabola is
y=x²+5
the equation of a horizontal parabola in vertex form
x=a*(y-k)²+h
(h,k)------> (0,5)
x=a*(y-5)²+0
x=a*(y-5)²
substitute the point (2,9) in the equation
2=a*(9-5)²------> 2=16*a------> a=1/8
the equation of the horizontal parabola is
x=(1/8)*(y-5)²
the answer isthe equation of the vertical parabola is y=x²+5
the equation of the horizontal parabola is x=(1/8)*(y-5)²
see the attached figure
Answer:its a triangle looking for the points and which are similar
Step-by-step explanation:
Rewrite then factor as a difference of cubes:
1 - 64<em>x</em>³ = 1³ - (4<em>x</em>)³
= (1 - 4<em>x</em>) (1² + 4<em>x</em> + (4<em>x</em>)²)
= (1 - 4<em>x</em>) (1 + 4<em>x</em> + 16<em>x</em>²)
Answer:
2/5y and -0.2y
-6 and -2
Step-by-step explanation:
Here, we want to select the pair of like terms
To do this, we finish the evaluation of the expression
2/5y + 1/5x - 0.2y -6+ (-2)
We have the two y’s together
2/5y and -0.2y
-6 and -2
Answer:
92
−
22
=
70
.
70
Step-by-step explanation:
subtract and add