1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nina [5.8K]
3 years ago
10

To dive far below the surface of the water, a submarine must be able to withstand enormous pressures. At a depth of 351 m, what

pressure does water exert on the submarine’s hull? Use g=9.81 m/s2.
Physics
1 answer:
Stells [14]3 years ago
8 0

Answer:

P=3647934.3 Pa

Explanation:

We use the formula for pressure inside a fluid:

P=P_0+\rho g h

Where P_0 is the pressure at its surface (the atmospheric pressure in our case), \rho its density (the density of seawater in our case), <em>g</em> the acceleration of gravity (which is given in our case, and known) and <em>h</em> the depth at which we want to know the pressure (which is given in our case). For our case then we have:

P=101325Pa+(1030kg/m^2)(9.81m/s^2)(351m)=3647934.3Pa

You might be interested in
A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the
Sergio039 [100]

Answer:

W = 1.06 MJ

Explanation:

- We will use differential calculus to solve this problem.

- Make a differential volume of water in the tank with thickness dx. We see as we traverse up or down the differential volume of water the side length is always constant, hence, its always 8.

- As for the width of the part w we see that it varies as we move up and down the differential element. We will draw a rectangle whose base axis is x and vertical axis is y. we will find the equation of the slant line that comes out to be y = 0.5*x. And the width spans towards both of the sides its going to be 2*y = x.

- Now develop and expression of Force required:

                                             F = p*V*g

                                             F = 1000*(2*0.5*x*8*dx)*g

                                             F = 78480*x*dx

- Now, the work done is given by:

                                             W = F.s

- Where, s is the distance from top of hose to the differential volume:

                                             s = (5 - x)

- We have the work as follows:

                                            dW = 78400*x*(5-x)dx

- Now integrate the following express from 0 to 3 till the tank is empty:

                                           W = 78400*(2.5*x^2 - (1/3)*x^3)

                                           W = 78400*(2.5*3^2 - (1/3)*3^3)

                                           W = 78400*13.5 = 1058400 J

 

5 0
3 years ago
A train increase its speed steadily from 10m/s to 20m/s in 1minutes A what is the average speed during this time in m/s B how fa
Ipatiy [6.2K]

If it increased its speed steadily at a constant rate, then the average speed for the minute was

(1/2)(10m/s + 20m/s) = 15 m/s .

Rolling at an average speed of 15 m/s for 1 minute (60 seconds), it travels

(15 m/s) (60 sec) = 900 meters

3 0
3 years ago
You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand at 30 m/s. What is the kinetic energy (KE) of the volley
FinnZ [79.3K]

awnser :

Explanation:

8 0
2 years ago
Read 2 more answers
Please help me, please i will mark brainliest
abruzzese [7]

Answer:

conductor,neither,insulator

Explanation:

conductors allow electricity to flow through while insulators do not

HOPE IT HELPS

5 0
2 years ago
Read 2 more answers
Hola tengo un taller de física y nose como resolver este pregunta
Blizzard [7]

a) 0.26 h

b) 71.4 km

Explanation:

a)

In order to solve the problem, we have to know what is the final velocity of the car.

Here, we assume that the final velocity reached by the car is

v=300 km/h

Therefore, we can find the time taken by the car to reach this velocity by using the suvat equation:

v=u+at

where:

u = 250 km/h is the initial velocity

a=190 km/h^2 is the acceleration of the car

v = 300 km/h is the final velocity

t is the time

Solving for t, we find:

t=\frac{v-u}{a}=\frac{300-250}{190}=0.26 h

b)

In order to find the distance covered by the car, we can use the following suvat equation:

s=ut+\frac{1}{2}at^2

where:

s is the distance covered

u is the initial velocity

a is the acceleration

t is the time

For the car in this problem, we have:

u = 250 km/h

t = 0.26 h (calculated in part a)

a=190 km/h^2

Therefore, the distance covered is

s=(250)(0.26)+\frac{1}{2}(190)(0.26)^2=71.4 km

8 0
2 years ago
Other questions:
  • What is potential energy of a 10.0 kg weight suspended 3.0m above the ground?
    13·1 answer
  • A skier moving at 4.75 m/s encounters a long, rough, horizontal patch of snow having a coefficient of kinetic friction of 0.220
    14·1 answer
  • Hi, Solve for λ<br> E=hc/λ
    13·1 answer
  • A proton enters a uniform magnetic field of strength 1 T at 300 m/s. The magnetic field is oriented perpendicular to the proton’
    14·1 answer
  • Calculate the wave length of a water wave with a speed of 20 m/s and a frequency of 2.5 Hz
    8·1 answer
  • The results of a recent television survey of American TV households revealed that 86 out of every 100 TV households have at leas
    5·1 answer
  • Two sources of in-phase coherent sound are located at the points (0 m, 2 m) and (-2 m, 0 m). An observer at the origin hears con
    14·1 answer
  • State the laws of reflection​
    8·1 answer
  • The law of Conservation of energy states that energy can be transformed from one form to another, but it cannot be _______ or __
    10·2 answers
  • If i am changing velocity, i must also have _______ and a net _________
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!