1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bond [772]
3 years ago
9

Justin Bieber is thrown horizontally at 10.0 m/s from the top of a cliff 122.5 m high.

Physics
2 answers:
sveticcg [70]3 years ago
7 0

===>  Distance fallen from rest in free fall =

                                         (1/2) (acceleration) (time²)

                               (122.5 m) = (1/2) (9.8 m/s²) (time²)

Divide each side by (4.9 m/s²):   (122.5 m / 4.9 m/s²)  =  time²

                                                           (122.5/4.9) s²  =  time²

Take the square root of each side:    5.0 seconds


===> (Accelerating at 9.8 m/s², he will be dropping at
                               (9.8 m/s²) x (5.0 s) = 49 m/s
when he goes 'splat'.  We'll need this number for the last part.)


===> With no air resistance, the horizontal component of velocity
doesn't change.

Horizontal distance = (10 m/s) x (5.0 s)  =  50 meters .

===>  Impact velocity =  (10 m/s horizontally) + (49 m/s vertically)

                                 = √(10² + 49²)  =  50.01 m/s  arctan(10/49)

                                 =    50.01 m/s   at  11.5° from straight down,
                                                           
away from the base of the cliff.  

ivann1987 [24]3 years ago
4 0

Answer:

===>  Distance fallen from rest in free fall =

                                        (1/2) (acceleration) (time²)

                              (122.5 m) = (1/2) (9.8 m/s²) (time²)

Divide each side by (4.9 m/s²):   (122.5 m / 4.9 m/s²)  =  time²

                                                          (122.5/4.9) s²  =  time²

Take the square root of each side:    5.0 seconds

===> (Accelerating at 9.8 m/s², he will be dropping at

                              (9.8 m/s²) x (5.0 s) = 49 m/s

when he goes 'splat'.  We'll need this number for the last part.)

===> With no air resistance, the horizontal component of velocity

doesn't change.

Horizontal distance = (10 m/s) x (5.0 s)  =  50 meters .

===>  Impact velocity =  (10 m/s horizontally) + (49 m/s vertically)

                                = √(10² + 49²)  =  50.01 m/s  arctan(10/49)

                                =    50.01 m/s   at  11.5° from straight down,

                                                           away from the base of the cliff.  

Explanation:

Just saying i LOVE him

You might be interested in
A 420-turn circular coil with an area of 0.0650 m2 is mounted on a rotating frame, which turns at a rate of 22.3 rad/s in the pr
Ivenika [448]

Answer:

33.48 V

Explanation:

Parameters given:

Number of turns, N = 420

Magnetic field strength, B = 0.055 T

Area, A = 0.065 m²

Angular velocity, ω = 22.3 rad/s

EMF induced in a coil is given as:

EMF = -dΦ/dt

where Φ = magnetic flux

Magnetic flux, Φ, is given as:

Φ = B * N * A * cosωt

EMF = -d( B * N * A * cosωt) / dt

EMF = B * N * A * ω * sinωt

where ωt = 90°

Therefore:

EMF = 0.055 * 420 * 0.065 * 22.3 * sin90°

EMF = 33.48 V

7 0
3 years ago
An atom has 25 protons 30 neutrons and 25 electrons what is the charge of the atom nucleus
Alex17521 [72]
The nucleus is always positive since thats where the protons are located and the neutrons have no charge....
3 0
3 years ago
Does the speed of the object affect friction?
Volgvan

Answer:

it would

Explanation:

this is because as something rubs against a surface fast, friction heats it up, like when you rub a surface fast and it gets warm on the palm of your hand, that is friction. hope it helped :)

6 0
3 years ago
For a satellite of mass mS in a circular orbit of radius rS around the Earth, determine its kinetic energy, K . Express your ans
agasfer [191]

Since it is asking you to find the kinetic energy in relation to the mass, radius, mechanical energy (total energy), and constants, you will need to setup an equation first to "find" the Mechanical Energy, so that we can then solve for the kinetic energy, as from my experience with high school physics, there is only the graviational potential energy equation and force in relation to celestial bodies.

Knowing the ME is the total energy, we add up the energies of the system. Since it is being influenced by the Earth, as per the problem stating the satellite has circular orbit around the Earth, we know there is gravitational potential. Since it is orbiting, we can assume some type of velocity. Nothing else that we need to worry about should be occuring at this level of physics, leaving you with

ME= Ug+K

from here we solve for K, as plugging in could get confusing and messy at the moment.

ME-Ug=K

now using the equations presumably given in class, if not then using this equation, we can find the Ug

Ug=(-(Gm*M)/r)     note that M is the mass of the Earth and m is the satellite

this should give us

ME-(-(GmM)/r)=K

since there is a negative being subracted, we can change that to

ME+(GmM)/r=K

I believe this should be fine, as the Earth's mass is constant, but if not, then all you need to figure left is how to get rid of the M in the equation, as the rest of the terms and constants are for sure within the requirements.

8 0
3 years ago
A star has an absolute magnitude of 4 and a surface temperature of 5,000 degrees C. According to the HR diagram, list the type o
Ierofanga [76]
On sources it says it would  just be the super giant star 
3 0
3 years ago
Other questions:
  • Consider the binding energy of two stable nuclei, one with 60 nucleons and one with 200 nucleons. a. Is the total binding energy
    11·1 answer
  • What is threshold frequency
    7·2 answers
  • Flywheels are large, massive wheels used to store energy. They can be spun up slowly, then the wheel's energy can be released qu
    8·1 answer
  • This is a ______________________reaction.
    9·2 answers
  • Temperature of 273K is the temperature at which water
    14·1 answer
  • Date
    7·1 answer
  • A child weighing 200 N is being held back in a swing by a horizontal force of 125 N, as shown in the image. What is the tension
    10·1 answer
  • Ram covers distance of zoom in 50 seconds what is his speed​
    7·1 answer
  • Please Help!!!!!
    10·1 answer
  • NEED HELP!!!! 15 POINTS!!!!!!!
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!