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BARSIC [14]
3 years ago
15

You are camping with two friends, Joe and Karl. Since all three of you like your privacy, you don't pitch your tents close toget

her. Joe's tent is 18.5 m from yours, in the direction 23.0 ∘ north of east. Karl's tent is 41.0 m from yours, in the direction 37.5 ∘ south of east.

Physics
1 answer:
aleksklad [387]3 years ago
6 0

Answer:

35.7 m

Explanation:

Let

\mid A\mid=18.5 m

\mid B\mid=41 m

We have to find the distance between Joe's and Karl'e tent.

A_x=Acos\theta

A_y=Asin\theta

Substitute the values then we get

A_x=18.5cos23^{\circ}=17 m

A_y=18.5sin 23^{\circ}=7.2 m

B_x=41cos37.5^{\circ}=32.5 m

B_y=41sin37.5^{\circ}=-24.96 m

Because vertical component of B lie in IV quadrant and y-inIV quadrant is negative.

By triangle addition of vector

B=A+C

C=B-A

C_x=B_x-A_x=32.5-17=15.5 m

C_y=B_y-A_y=-24.96-7.2=-32.16\approx=-32.2 m

\mid C\mid=\sqrt{C^2_x+C^2_y}

\mid C\mid=\sqrt{(15.5)^2+(-32.2)^2}=35.7 m

Hence, the distance between Joe's and Karl's tent=35.7 m

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5 0
3 years ago
Lemon falling at a constant speed from a tree with no air resistance, draw a free body diagram
HACTEHA [7]

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8 0
3 years ago
Do complex machine need fuel​
Salsk061 [2.6K]

Answer:

car is a complex compound machine, that is fueled by gasoline to create motion. In a car, the engine is responsible for producing the power that causes the wheels to turn. The engine turns a rod called a crankshaft which is connected to the drive shaft which in turn is connected to the axle which of course is connected to the wheels.

Gasoline is pumped into the gas tank of the car. From the gas tank, the fuel travels through the fuel line and reaches either the carburetor or fuel injector. From this point the gas flow is controlled by the amount of pressure placed on the accelerator. The fuel is converted into a mist much like a perfume by the carburetor. This "perfume" is then released into the cylinders where it is compressed, ignited, and exploded. Each time an explosion takes place the pistons are forced down, causing the crankshaft to turn. With each turn of the crankshaft comes a turn of the driveshaft and with each turn of the driveshaft, comes a turn of the axle and consequently the wheels.

A car is a complicated and complex machine that is dependent upon the laws of physics for both efficiency and performance. Nearly all the laws of physics can be found in the workings of an automobile. Friction between the rubber tires and asphalt ground is the reason why the car moves (aside from all the workings of the engine). To better improve friction, tires are built and designed with tread patterns that grip the asphalt road more efficiently.

Aerodynamics is also a great factor when it comes to designing cars. Air resistance can contribute greatly to low gas mileage and poor efficiency. As a result, car manufacturers design automobiles with pointed fronts, rounded bodies, and streamlined patterns. With these designs the air can be "cut" so that it does not act like a block stopping the car. A good way to test the notion of air resistance is to put a hand out of a car when going down the freeway. A vertical hand pointing straight up will encounter great air resistance while a horizontal hand will encounter hardly any. This is the reason why cars are pointed in the front and not flat.

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Explanation:

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3 0
3 years ago
65 POINTS! PLEASE ANSWER EVERY QUESTION! NEED HELP ASAP!
otez555 [7]
Maybe you can split up the questions. I will try to answer your first question.

1. In an elastic collision, momentum is conserved. The momentum before the collision is equal to the momentum after the collision. This is a consequence of Newton's 3rd law. (Action = Reaction)

2. Momentum: p = m₁v₁ + m₂v₂

m₁ mass of ball A
v₁ velocity of ball A
m₂ mass of ball B
v₂ velocity of ball B

Momentum before the collision:
p = 2*9 + 3*(-6) = 18 - 18 = 0

Momentum after the collision:
p = 2*(-9) + 3*6 = -18 + 18 = 0

3: mv + m(-v) = m(-v) + m(v)
the velocities would reverse.

4.This question is not factual since the energy of an elastic collision must also be conserved. The final velocities should be: v₁ = -1 m/s and v₂ = 5 m/s. That said assuming the given velocities were correct:
before collision
p = 10*3 + 5*(-3) = 30 - 15 = 15
after collision:
p = 10*(-2) + 5 * v₂ = 15
v₂ = 7

5.You figure out.



3 0
3 years ago
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