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nasty-shy [4]
3 years ago
6

Sara has 20 sweets.

Mathematics
2 answers:
sdas [7]3 years ago
4 0
17/29 + 6/29 + 4/29
= 27/30
<span>1 - 27/29 = 2/29 = 0.069</span>
Ber [7]3 years ago
3 0
Simple probability question. 

The probability that the 2 sweets will not be the same = 1 - probability of same 2 sweets.

There are 3 possible outcomes where the two sweets will be the same. If she had 2 Liquorice or 2 mint or 2 humbug.

P(2 Liquorice) = 12/20 * 11/19
P(2 Mint) = 5/20 *4/19
P(2 Humbug) = 3/20 * 2/19

<span>All of those added together will give you the probability of her getting 2 of the same time of sweet. </span>

You the take that answer and subtract it from 1.


<span>I hope that helps.</span>
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How do you simplify:<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%28125%20%5E%7B2%7D%20%7D%20%29%20%20%20%5E%7B%20-%20
Nady [450]

Answer:

\huge\boxed{\sqrt{(125^2)^{-\frac{1}{3}}}=\dfrac{1}{5}}

Step-by-step explanation:

\sqrt{(125^2)^{-\frac{1}{3}}}\qquad\text{use}\ (a^n)^m=(a^m)^n\\\\=\sqrt{\left(125^{-\frac{1}{3}\right)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=125^{-\frac{1}{3}}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{1}{125^\frac{1}{3}}\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\dfrac{1}{\sqrt[3]{125}}=\dfrac{1}{5}\qquad\text{because}\ 5^3=125

5 0
3 years ago
The Sun is roughly 10^2 times as wide as the Earth. The Star KW Sagittarii is roughly 10^5 times as wide as the Earth. About how
Studentka2010 [4]

Answer:

1000 times

Step-by-step explanation:

Given:

The Sun is roughly 10^2 times as wide as the Earth.

The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.

Question asked:

About how many times as wide as the Sun is KW Sagittarii?

Solution:

Let the width of the earth =  x

As the Sun is roughly 10^2 times as wide as the Earth, hence the width of the sun = x\times10^{2}

And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star = x\times10^{5}

Now, to find that how many times width of the Star  KW Sagittarii is as respect to the width of the Sun, we will simply divide:

Width of the Star  KW Sagittarii =  x\times10^{5}

Width of the Sun = x\times10^{2}

\frac{x\times10^{5} }{x\times10^{2} }

x canceled by x

\frac{10^{5} }{10^{2} } =10^{5-2} =10^{3} =10\times\ 10\times10=1000

Therefore, Star  KW Sagittarii is 1000 times wider than Sun.

<em>First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.</em>

<em />

4 0
3 years ago
Write 1.50 as a mixed number
GaryK [48]
The answer is 150 over 100 hope this helps
4 0
3 years ago
AE and DF are parallel. If √ABG = 11x and m_HCF = 10x + 9, what is m√ABG? 102° 99° 81° 9° ​
katrin [286]

Answer:

81

Step-by-step explanation:

6 0
3 years ago
In the diagram of circle A, what is m angle LMN?<br> О 75°<br> O90°<br> О 120°<br> 135°<br> ОО
Jet001 [13]

Answer:

90

Step-by-step explanation:

Angle Formed Outside = 1/2(DIFFERENCE of Intercepted Arcs)

ARC LN = 360 - 270 =90

LMN  = 1/2(270 -90)

         = 1/2 (180)

        = 90

3 0
3 years ago
Read 2 more answers
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