Answer: The correct answer would be 45ft and 36ft
Hopefully this helps:) Mark me the Brainliest:))!!
X=number looked for
we have this equation:
-52(x-14)=x+3
we solve this equation:
-52x+728=x+3
-52x-x=3-728
-53x=-725
x=-725/-53=725/53 ≈13,68
Solution: 725/53
To check:
the difference between 725/53 and 14=725/53 - 14=(725-742)/53=-17/53
-52 times the diference is= -52(-17/53)=884/53
The number plus 3=725/53 + 3=(725+159)/53=884/53
Hi there!
In order to solve, we'll need to use a proportion: 20/a = 21/20. Then, we'll cross-multiply and solve to find a: 21a = 400 | a = 19.05. Next, to find b, we can just use pythagorean theorem: 20^2 + (400/21)^2 = b^2 | b = 27.62.
We are using geometric mean to solve for a, then using pythagorean theorem to solve for b. If you need more help with geometric mean, or would like a complete explanation, please let me know! I'd be happy to provide you with that information.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
2.625 is 21/8 into a decimal
The wall area is the product of the room perimeter and the room height:
A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²
The window and door area together is
A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²
The area of one roll of wallpaper is
A₃ = (2.5 ft)*(30 ft) = 75 ft²
Then the number of rolls of wallpaper required will be
1.1*(A₁ - A₂)/A₃ ≈ 4.74
5 rolls of wallpaper should be purchased.
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As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).
