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2 years ago

What is differentiation ?

2 answers:

7 0

<h2 /><h2> $Differentiation \: is \: a \\ method \: of \: finding \: the \\ derivative \: of \: a \: function. \\ Differentiation \: is \: a \\ process, \: in \: Maths, \: where \\ we \: find \: the \: instantaneous \\ rate \: of \: change \: in \: function \\ based \: on \: one \: of \: its \: variables. \\ The \: most \: common \: example \\ is \: the \: rate \: change \: of \\ displacement \: with \: respect \: to \\ time, \: called \: velocity.$ </h2>

sergij07 [2.7K]2 years ago

4 0

Answer:

differentiate

for example what is difference between this and that

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Please help. with question number 16

ddd [48]

Answer:

12/5

Step-by-step explanation:

All you do is multiply

8 0

3 years ago

jen picked 3/4 of a gallon of strawberries in a half of hour .if she keeps picking strawberries at the same rate.how many gallon

ivolga24 [154]

3 gallons of strawberries.

3/4 * 4/1 = 12/4 = 3

or you can use the butterfly method on the fours and get

3/1 * 1/1 = 3

5 0

3 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

3 0

3 years ago

Which of the following ordered pairs could be placed in the table and still have the relation qualify as a linear function? (4 p

Lerok [7]

Answer:

(2, 7)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A gardener wishes to plant plants in such a way that each row contains as many plants as the number of rows. He has 2624 plants.

vagabundo [1.1K]

Answer:

Step-by-step explanation:

we search for a square number so that rows*plantsInARow gives us the number

The number should be around 50², guessed

50² = 2500 (to low)

51² = 2601 (still to low)

52² = 2704 (bingo)

now to get from 2624 to 2704 plants he needs 80 more. That is the least number.

He could also go to plant 60² plants an than need slot more.

(would really appreciate the brainliest)

8 0

3 years ago