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alexdok [17]
3 years ago
5

Four points are labeled on the number line.Which point represents the value |-1 1/2|?

Mathematics
2 answers:
Bingel [31]3 years ago
7 0

Answer:

Point Q   -0.5

Step-by-step explanation:

Negative 1/2 is equal to -0.5

alukav5142 [94]3 years ago
4 0

Answer: -1

Step-by-step explanation:

i really don't know but i was taking a test and i guessed it and it was right

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What is formed when two complementary angles share one ray?
aleksklad [387]

Answer:

B.

the complementary angles form a right angle with the shared ray

5 0
3 years ago
= 118
oee [108]

Answer:

number of $20 bill = 4

Number of $5 bill = 5

Step-by-step explanation:

Given that:

Total number of $5 and $20 bills = 9

Let :

Number of $5 bills = x

Number of $20 bills = y

Combined worth of all bills = $105

x + y = 9 - - - (1)

5x + 20y = 105 - - - (2)

From (1)

x = 9 - y

Substitute x = 9 - y into (2)

5(9 - y) + 20y = 105

45 - 5y + 20y = 105

15y = 105 - 45

15y = 60

y = 60/15

y = 4

x = 9 - y

x = 9 - 4 = 5

Hence,

number of $20 bill = 4

Number of $5 bill = 5

6 0
3 years ago
Hana rents a car for a day. Her car rental company charges $50 per day and $0.40 per mile. Peter rents a car from a different co
erastova [34]

50 + .4x = 70 + .3x

.4x = .3x + 20

.1x = 20

x = 200

Let x be the number of miles.

They have to drive 200 miles.

4 0
3 years ago
A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three diff
igor_vitrenko [27]

Answer:

(a) 31101

(b) $5.65

(c) $113.38

Step-by-step explanation:

The complete question is:

A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three different prizes: an automobile valued at $20,000, a $125 gas card, or a $5 shopping card. To claim his or her prize, a prospective print on the back of the flier listed the probabilities of winning. The chance of winning the car was 1 out of 31,101, the chance of winning the gas card was 1 out of 31,101, and the chance of winning the shopping card was 31, 099 out of 31,101.

Solution:

The information provided is as follows:

P(\text{Car})=\frac{1}{31101}\\\\P(\text{Gas Card})=\frac{1}{31101}\\\\P(\text{Shopping Card})=\frac{31099}{31101}

(a)

The number of fliers the automobile dealership sent​ out is, <em>n</em> = 31,101.

This is because the probability of winning any of the three prize is out of 31,101.

(b)

Compute the expected value of the prize won by a prospective customer receiving a​ flier as follows:

E(X)=\sum x\times P(X=x)

         =[20000\times \frac{1}{31101}]+[125\times \frac{1}{31101}]+[5\times \frac{31099}{31101}]\\\\=0.6431+0.0040+4.9997\\\\=5.6468\\\\\approx 5.65

Thus, the expected value of the prize won by a prospective customer receiving a​ flier is $5.65.

(c)

Compute the standard deviation of the prize won by a prospective customer receiving a​ flier as follows:

SD(X)=\sqrt{V(X)}=\sqrt{E(X^{2}-(E(X))^{2}}

           =\sqrt{[(20000)^{2}\times \frac{1}{31101}+(125)^{2}\times \frac{1}{31101}+(5)^{2}\times \frac{31099}{31101}]-(5.65)^{2}}\\\\=\sqrt{12854.9011}\\\\=113.37947\\\\\approx 113.38

Thus, the standard deviation of the prize won by a prospective customer receiving a​ flier is $113.38.

8 0
3 years ago
I need help please and thank you
Sergeeva-Olga [200]
A is the answer

Hope this helps
4 0
3 years ago
Read 2 more answers
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