Find three consecutive odd integral such that the sum of seven times the smallest and twice the largest is -91
2/5 of 30 = 12
30 + 12 = 42
£42
Step-by-step explanation:
<em>1st year</em>:
(1200 x 3.5 x 1) ÷ 100 = $42
<em>2nd year:</em>
(1242 x 3.5 x 1) ÷ 100= $43.47
<em>3rd year:</em>
(1285.47 x 3.5 x 1) ÷ 100= $44.99≈ $45
<em>4th year:</em>
(1330.47 x 3.5 x 1) ÷ 100= $46.56
Compound interest:
$(42 + 43.47 + 45 + 46.56)
=<u>$ 177.03</u>
The answer is 60 because
40-10*2=60
hope it helps
If you turn the ratio 1:3 into a fraction it would be 1 over 3 I hope this helps
