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castortr0y [4]
3 years ago
14

A football player weighed 170 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall practice

, he lost 10 1/4 pounds, and during the second week, he lost another 3 1/2 pounds. How much did he weigh at that point?
Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

he now weighs a total of 182 pounds.

hopefully thats right if not im sorry :c

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Write an equation of the line in slope-intercept form. (Pls answer fast)<br><br> Y=
nydimaria [60]

Answer:

y =  -  \frac{1}{4} x + 3

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2 years ago
Allison has five times as many baseball cards as football cards and all she has 120 baseball and football cards how many basebal
Shtirlitz [24]
The answer is 600 because you have to multiply 120 by 5 and the sum is 600 
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3 years ago
Using the simple random sample of weights of women from a data​ set, we obtain these sample​ statistics: nequals45 and x overbar
Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : n=45

\overline{x}=148.79\text{ lb}

\sigma=31.37\text{ lb}

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = \mu=148.79\text{ lb}

b) The confidence interval for the population mean is given by :-

\mu\ \pm E, where E is the margin of error.

Formula for Margin of error :-

z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given : Significance level : \alpha=1-0.90=0.1

Critical value : z_{\alpha/2}=z_{0.05}=\pm1.645

Margin of error : E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69

Now, the 90% confidence interval for the population mean will be :-

148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)

Hence, the 90​% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0
3 years ago
School lunch costs $1.25 per day. If there are 21 school days
prohojiy [21]

Answer:

$26.25

Step-by-step explanation:

1.25 per day

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3 0
2 years ago
Read 2 more answers
Solve x4 – 17x2 + 16 = 0.<br> Let u =<br> Select all of the zeroes of the function. i i
Soloha48 [4]

Solve \ x^4 - 17x^2 + 16 = 0

To solve this equation , we need to write it in quadratic form

ax^2+bx+c=0

To get the equation in quadratic form we replace x^2 with u

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x^4 - 17x^2 + 16 = 0 can be written as

(x^2)^2 - 17x^2 + 16 = 0, Replace u for x^2

So equation becomes

u^2 - 17u + 16 = 0

Now we factor the left hand side

-16  and -1  are the two factors whose product is +16  and sum is -17

(u-16) (u-1) = 0

u -16 = 0  so u=16

u-1 =0  so u=1

WE assume u = x^2, Now we replace u with x^2

u = 16 so \ it \ becomes \ x^2 =16

Now take square root on both sides , x= +4  and x=-4

u = 1 so \ it \ becomes \ x^2 =1

Now take square root on both sides , x= +1  and x=-1

So zeros of the function are -4, -1, 1, 4


8 0
3 years ago
Read 2 more answers
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