Question

If the areas of the given pairs of shapes are equal, find the value of x.​

Answer 1

Answer:

X= 8cm

Step-by-step explanation:

area of the square = s×s = 16×16 = 256cm

area of the rectangle = l×b = 32×x = 32x

Given , area of triangle = area of square

32x = 256

x= 256/32

x= 8cm

Answer 2

Answer:

$x = 8cm$

Step-by-step explanation:

we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e

• the area of the square equal to the area of the rectangle

therefore,

$\displaystyle \rm A _{square } = A _{rect}$

recall the formula of the area of square and rectangle so,

$\displaystyle {s}^{2} = lw$

now assign variables

• $s \implies16cm$
• $l \implies32cm$
• $w \implies x$

thus substitute:

$\displaystyle 32cmx = {16cm}^{2}$

simplify square:

$\displaystyle 32cmx = 256cm^2$

divide both sides by 32:

$\displaystyle \boxed{x = 8cm}$

and we're done!