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Otrada [13]
2 years ago
12

If the areas of the given pairs of shapes are equal, find the value of x.​

Mathematics
2 answers:
Grace [21]2 years ago
8 0

Answer:

X= 8cm

Step-by-step explanation:

area of the square = s×s = 16×16 = 256cm

area of the rectangle = l×b = 32×x = 32x

Given , area of triangle = area of square

32x = 256

x= 256/32

x= 8cm

den301095 [7]2 years ago
3 0

Answer:

x = 8cm

Step-by-step explanation:

we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e

  • the area of the square equal to the area of the rectangle

therefore,

\displaystyle \rm A _{square } = A _{rect}

recall the formula of the area of square and rectangle so,

\displaystyle  {s}^{2} = lw

now assign variables

  • s \implies16cm
  • l \implies32cm
  • w \implies x

thus substitute:

\displaystyle 32cmx =  {16cm}^{2}

simplify square:

\displaystyle 32cmx = 256cm^2

divide both sides by 32:

\displaystyle  \boxed{x = 8cm}

and we're done!

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“a” would equal 7!! hope this helps :)
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