Question

You have the following items ready to use for making solutions: Glucose (solid; MW=180g/mol) 1M Tris HCl (liquid solution;MW= 158g/mol ) Acetone (liquid; MW=58g/mol) 10% agarose (liquid solution; MW=631g/mol) Your instructions state that you need to make 500ml of 0.5M glucose solution. Match the following information to prepare to conduct the math required to generate this specific glucose solution. Not all choices will be used.
1234567 Final Concentration (Cf or C2)

1234567 Original volume or amount (Vo or V1)

1234567 Final volume (Vf or V2)

1234567 Original concentration (Co or C1)

1. N/A - solute source is not in solution
2. To be determined (your unknown)
3. 1M
4. 500 ml
5. 0.25M
6. 10%
7. 10 ml

Answer 1

Answer:

See explaination

Explanation:

original concentration is the concentration of the stock solution that we have. so Vo = For Tris HCl 1M

final concentration is the concentration of the solution that we need - V2 = Tris HCl it is 0.25 M

Original volume or amount is the volume of the original solution that we need to add in the water or diluent to get final volume - Vo = To be determined (your unknown)

The final volume is the volume that we need for the solution - V2 = 10ml

According to the law of equilibrium

V1C1 = V2 C2

V1 * 1 = 0.25 *10

V1 = 0.25*10/1

V1 = 2.5ml.

So we need 2.5 ml of 1M TRIS- HCl.