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abruzzese [7]
3 years ago
11

An unknown liquid has a vapor pressure of 88 mmhg at 45°c and 39 mmhg at 25°c. What is its heat of vaporization?

Chemistry
1 answer:
Elis [28]3 years ago
6 0

The relation between vapour pressure , enthalpy of vapourisation and temperature is

ln(\frac{P1}{P2} ) = \frac{deltaH}{R} (\frac{1}{T2} - \frac{1}{T1})

ln (88/ 39) = DeltaH / 8.314 (1 / 318 - 1 / 298)

0.814 = DeltaH / 8.314 (2.11 X 10^-4 )

DeltaH = -32.07 kJ


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4 0
3 years ago
Read 2 more answers
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8 0
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