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Setler79 [48]
3 years ago
5

Thallium-201 is a radioactive isotope that undergoes first-order decay. When the concentration of 201Tl is 0.0042 M, its half-li

fe is 73.0 hours. What is the half-life of 201Tl when its concentration is 0.0136 M?(A) 51.0 hours(B) 73.0 hours(C) 123 hours(D) 236 hours
Chemistry
1 answer:
9966 [12]3 years ago
7 0

Answer:

(B) 73.0 hours.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

<em>So, the half-life of 201Tl when its concentration is 0.0136 M is (B) 73.0 hours.</em>

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Since a parallelogram is defined as a quadrilateral with two pairs of parallel sides, Emily drew in a diagonal of a parallelogra
koban [17]

Explanation:

In the attachment fig ABCD is a parallelogram with AC as diagonal.

we know that,

In  a parallelogram opposite sides are equal and parallel

In a parallelogram sum of adjacent angles is 180°

that is

∠A+∠D= ∠B+∠C= 180°

Also, in  a parallelogram opposite angles are equal.

So in ΔADC and ΔABC

1) AD=BC

2) DC= AB

And

3) ∠ADC= ∠ABC

therefore, ΔADC and ΔABC are congruent to each other and Emily was right.

6 0
3 years ago
Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissol
Stells [14]

Here is the complete question.

Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissolves readily in water and polar organic solvents like ethanol. Calculate the mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol (CH3CH2OH; density = 0.7893 g/mol). Round to four significant digits

Answer:

0.9567 mol

Explanation:

Given that:

mass of glycerol = 1.61 g

molar mass of glycerol = 92.1 g/mol

no of mole = \frac{mass}{molar mass}

∴ number of moles of glycerol (n_{glycerol}) = \frac{1.61}{92.1}

= 0.0175 mol

Volume of ethanol = 22.60 mL

Density of ethanol = 0.7893 g/mL

Since Density = \frac{mass}{volume}

∴  mass of ethanol = density of ethanol × volume of ethanol

mass of ethanol =  0.7893 g/mL × 22.60 mL

mass of ethanol =  17.838 g

Number of moles of ethanol (n_{ethanol}) = \frac{17.838}{46.0684}

= 0.387 mole

∴ the mole fraction of the solvent can be determined as:

X_{solvent} = X_{ethanol} = \frac{n_{ethanol}}{n_{glycerol}+n_{ethanol}}

=\frac{0.387 mol}{(0.0175+0.387)mol}

= \frac{0.387mol}{0.4045mol}

= 0.95673671199

≅ 0.9567 mol

∴ The mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol is = 0.9567 mol

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4 years ago
At what temp will a gas be at if you allow it to expand from an original 456 mL to 65°C to 3.4 L
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We use the gas law named Charle's law for the calculation of the second temperature. The law states that,
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                                (0.456 L)(65 + 273.15) = (3.4 L)(T₁)
                                             T₁ = 45.33 K
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3 years ago
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What did rutherfords gold foil experiment help him conclude
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It allowed him to realize that the mass of an atom is concentrated at its center because the atoms mostly went through the foil but some were deflected. He also realized that an atom probably wasn't just empty space and scattered electron and it had a positive center. 
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1 pts.what is the charge on the hydrogen end of a water molecule?
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Positive

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